How to Solve Quantum Mechanics Problems Using Commutation Relations

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Discussion Overview

The discussion revolves around solving quantum mechanics problems using commutation relations, specifically focusing on the relationship between the position operator and the Hamiltonian. Participants explore methods for transforming the position operator into a velocity form and the application of commutator techniques.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant expresses difficulty in using the commutation relation between the position operator and the Hamiltonian.
  • Another participant suggests multiplying the left-hand side by the energy denominator and inserting the Hamiltonian operator to apply the commutator trick.
  • A participant questions how to transform the position operator into a velocity form, indicating uncertainty about their procedure.
  • A later reply indicates that the initial confusion was resolved, acknowledging the previous advice as helpful.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the method for transforming the position operator, as there are differing approaches and some uncertainty remains regarding the initial procedure.

Contextual Notes

The discussion includes assumptions about the applicability of the commutation relations and the specific forms of the operators involved, which are not fully detailed.

kib97153
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http://ejokeimg.pchome.com.tw/see-post.html?Flow_No=30201&cat=47&rank="

I try using the commutation relation of the position operator and the Hamiltonian, but failed.:bugeye::bugeye:

Thanks for your kindly help!
 
Last edited by a moderator:
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By the way, I don't know how to show the pics directly, sorry about that.
 
Multiply the left hand side by the energy denominator. Insert the hamiltonian operator. The commutator trick should then work.
 
StatMechGuy said:
Multiply the left hand side by the energy denominator. Insert the hamiltonian operator. The commutator trick should then work.


Thanks for your reply.^^ You mean like this?
But it's not the original equation. I know that the commutator of position and Hamiltonian is equal to velocity multiplies by
i and hbar(positive or negative sign added). But what I want to know is how to transform the position operator "itself" into the "velocity form" in the first pic I posted. Or my procedure is simply incorrect?
 

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Ooooooooooops, I got through it, thanks for you help!
You are right! No further questions at all...
 

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