Proof of Commutator Operator Identity

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Peter Yu
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TL;DR
Proof of Commutator Operator Identity used in Harmonic Oscillator of Quantum Mechanics
Hi All,
I try to prove the following commutator operator Identity used in Harmonic Oscillator of Quantum Mechanics. In the process, I do not know how to proceed forward. I need help to complete my proof.
Many Thanks.

Equation showing the commutator of a-dagger and a^k equals -k times a^(k-1), with a-hat written as an operator.


Handwritten notes defining a+ as creation operator, a as annihilation operator, and k as a constant, with the start of a commutator proof [a+, a^k] = a+(a...a) - (a...a)a+ marked k times each, ending in a question about the next step.
 
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  • Handwritten notes defining a+ as the creation operator, a as the annihilation operator and k as a constant, then the start of the commutator [a+, a^k] expanded with k factors marked on each side, ending with the question 'what is the next step?' and the result -k(a)^(k-1).
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Well, If ##k## is a natural number (which seems to be an asumtion in your proof) I would recommend you to use mathematical induction.
 
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Thank you for your response.
Can you enlighten me on the approach.
 
Sorry I do not know. Can you give me some hints.
 
Peter Yu said:
Sorry I do not know. Can you give me some hints.
https://en.wikipedia.org/wiki/Mathematical_induction

Essentially, is to prove only two easier statements:
$$\left[\hat{a}^\dagger, \hat{a}\right]=-\hat{a}^0$$ and $$\left[\hat{a}^\dagger, \hat{a}^k\right]=-k\hat{a}^{k-1}\Longrightarrow \left[\hat{a}^\dagger, \hat{a}^{k+1}\right]=-(k+1)\hat{a}^{k}$$
 
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Peter Yu said:
[tex]\big[ \hat{a}^{\dagger} , \left( \hat{a}\right)^{k}\big] = - k \left( \hat{a}\right)^{k - 1}[/tex]
You can easily show that the commutator [itex]\big[ \hat{a}^{\dagger} , \hat{a} \big] = -1[/itex] has the following representation [tex]\hat{a} \to a \ \mbox{id}_{C^{\infty}} , \ \ \hat{a}^{\dagger} \to - \frac{d}{da} ,[/tex]
acting on the space [itex]C^{\infty}[/itex] of smooth functions of the variable [itex]a[/itex]. So, for any function [itex]f(a) \in C^{\infty}[/itex] and any [itex]p \in \mathbb{R}[/itex], you have [tex]\big[ \hat{a}^{\dagger} , (f(a))^{p} \ \mbox{id}_{C^{\infty}} \big] = - p \ (f(a))^{p-1} \ \frac{df}{da} \ \mbox{id}_{C^{\infty}} .[/tex]
 
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