Proof of Commutator Operator Identity

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Discussion Overview

The discussion revolves around proving a commutator operator identity relevant to the harmonic oscillator in quantum mechanics. Participants explore methods to complete the proof, particularly focusing on mathematical induction and the properties of commutators.

Discussion Character

  • Exploratory
  • Mathematical reasoning

Main Points Raised

  • One participant seeks assistance in proving a commutator operator identity.
  • Another suggests using mathematical induction, assuming that k is a natural number.
  • There is a request for clarification on the approach to mathematical induction.
  • Participants discuss the basic statements needed for induction, including specific commutator identities.
  • A later reply provides a representation of the commutator in terms of differential operators acting on smooth functions.

Areas of Agreement / Disagreement

The discussion does not reach a consensus, as participants express varying levels of understanding regarding mathematical induction and its application to the proof.

Contextual Notes

Some participants express uncertainty about mathematical induction and its steps, indicating a potential gap in foundational knowledge necessary for the proof.

Peter Yu
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TL;DR
Proof of Commutator Operator Identity used in Harmonic Oscillator of Quantum Mechanics
Hi All,
I try to prove the following commutator operator Identity used in Harmonic Oscillator of Quantum Mechanics. In the process, I do not know how to proceed forward. I need help to complete my proof.
Many Thanks.

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Well, If ##k## is a natural number (which seems to be an asumtion in your proof) I would recommend you to use mathematical induction.
 
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Thank you for your response.
Can you enlighten me on the approach.
 
Do you know what mathematical induction is?
 
Sorry I do not know. Can you give me some hints.
 
Peter Yu said:
Sorry I do not know. Can you give me some hints.
https://en.wikipedia.org/wiki/Mathematical_induction

Essentially, is to prove only two easier statements:
$$\left[\hat{a}^\dagger, \hat{a}\right]=-\hat{a}^0$$ and $$\left[\hat{a}^\dagger, \hat{a}^k\right]=-k\hat{a}^{k-1}\Longrightarrow \left[\hat{a}^\dagger, \hat{a}^{k+1}\right]=-(k+1)\hat{a}^{k}$$
 
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Peter Yu said:
\big[ \hat{a}^{\dagger} , \left( \hat{a}\right)^{k}\big] = - k \left( \hat{a}\right)^{k - 1}
You can easily show that the commutator \big[ \hat{a}^{\dagger} , \hat{a} \big] = -1 has the following representation \hat{a} \to a \ \mbox{id}_{C^{\infty}} , \ \ \hat{a}^{\dagger} \to - \frac{d}{da} ,
acting on the space C^{\infty} of smooth functions of the variable a. So, for any function f(a) \in C^{\infty} and any p \in \mathbb{R}, you have \big[ \hat{a}^{\dagger} , (f(a))^{p} \ \mbox{id}_{C^{\infty}} \big] = - p \ (f(a))^{p-1} \ \frac{df}{da} \ \mbox{id}_{C^{\infty}} .
 
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