How to Solve the Complex Polynomial Product Equation?

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Homework Help Overview

The discussion centers around a complex polynomial product equation involving multiple factors and a resulting polynomial expression. Participants are examining the structure and properties of the equation, particularly focusing on the implications of the polynomial's degree and the behavior of its terms.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants suggest multiplying out the left side of the equation to analyze the resulting polynomial. Others question the nature of the exponents in the equation and whether they affect the solution process.

Discussion Status

The discussion has highlighted various interpretations of the polynomial's structure, including the cancellation of terms and the implications of the polynomial's degree. There is an ongoing exploration of the assumptions regarding the equation's setup and the potential for simplification through cancellation.

Contextual Notes

Participants note that the original poster did not provide evidence of their attempts to solve the problem, which is a requirement for seeking help in the forum. This has led to a discussion about adherence to forum rules.

anandzoom
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(1+x+x2+x3+x4+x5+x6+x7+x8)(1+x2+x4+x6+x8)(1+x3+x6)(1+x4+x8)(1+x5)(1+x6)(1+x7)(1+x8) = 1+x+2x2+3x3+5x4+7x5+11x6+15x7+22x8+...+x56
Please explain me the step-wise procedure to arrive at the solution.
 
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anandzoom said:
(1+x+x2+x3+x4+x5+x6+x7+x8)(1+x2+x4+x6+x8)(1+x3+x6)(1+x4+x8)(1+x5)(1+x6)(1+x7)(1+x8) = 1+x+2x2+3x3+5x4+7x5+11x6+15x7+22x8+...+x56
Please explain me the step-wise procedure to arrive at the solution.
Are those supposed to be exponents on the variable, x ?

Use that X2 feature in the green bar above the edit/composition box.
This gives something like: (1+x+x2+x3+x4+x5+x6+x7+x8)(1+x2+x4+x6+x8) ...

Furthermore:
You should use the supplied template when starting a thread, as well as showing an attempt at solving/understanding the problem you're presenting.
 
The only way I see to solve it is to multiply out the left side. Then move everything to one side and hope that many of the high-exponent terms disappear. Maybe there will only be a low order polynomial left. Look for the zeros of the polynomial.
 
Assuming those are exponents, that is a polynomial equation of degree 56. There exist "formulas" for polynomial equations of degree 4 or less but there is NO 'step by step" way of solving a general polynomial of degree five or higher and certainly not 56!
 
HallsofIvy said:
Assuming those are exponents, that is a polynomial equation of degree 56. There exist "formulas" for polynomial equations of degree 4 or less but there is NO 'step by step" way of solving a general polynomial of degree five or higher and certainly not 56!
I noticed that the x56 term cancels out. I assume the question has been rigged so that many terms cancel out.
 
FactChecker said:
I noticed that the x56 term cancels out. I assume the question has been rigged so that many terms cancel out.
Everything is in '+' ... terms can cancel out only if there is some '-' if I'm right
 
anandzoom said:
Everything is in '+' ... terms can cancel out only if there is some '-' if I'm right
Notice that both sides have +x56. (To see that on the left, scan through all that multiplication and notice that all the highest power terms multiply out to +x56). ) You can subtract x56 from both sides and the rest stays equal. My guess is that a lot of the high-power terms cancel out just like x56.
 
FactChecker said:
Notice that both sides have +x56. (To see that on the left, scan through all that multiplication and notice that all the highest power terms multiply out to +x56). ) You can subtract x56 from both sides and the rest stays equal. My guess is that a lot of the high-power terms cancel out just like x56.
My guess is that the right hand side is merely the expansion of the left hand side, so they ALL cancel.

OP still has not complied with PF rules.
 
In the homework help forums, posts seeking assistance must be accompanied by evidence of the member's attempt at solving the problem. No such evidence has been provided here.

Thread closed.
 

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