How to Solve the Difference Equation yn+1=(n+1)/(n+2) yn?

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Discussion Overview

The discussion revolves around solving the difference equation yn+1=(n+1)/(n+2) yn in terms of the initial value y0. Participants explore various methods and approaches to tackle the equation, including attempts to identify patterns and apply calculus concepts.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant suggests starting with yn=1/(n+1) y0 as a potential solution.
  • Another participant proposes using the Quotient Rule from calculus to approach the problem.
  • Several participants express uncertainty about how to begin solving the equation, indicating a lack of clarity on the initial steps.
  • One participant calculates specific values for y1, y2, y3, and y4, attempting to identify a pattern in the sequence.
  • Another participant challenges the relevance of calculus to the problem, suggesting that the issue is misidentified as a differential equation rather than a difference equation.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best approach to solve the difference equation. There are competing views regarding the applicability of calculus and the correct method for finding a solution.

Contextual Notes

Some participants express confusion about the distinction between difference equations and differential equations, which may affect their understanding of the problem. There is also a lack of clarity on the initial assumptions and steps needed to solve the equation.

Success
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Solve the difference equation yn+1=(n+1)/(n+2) yn in terms of the initial value y0.
 
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Hi Success! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:

(common-sense should solve this)
 
I really don't even know how to start. I guess you should begin with yn=1/(n+1) y0.
 
Use Quotient Rule

\frac{d}{dt}\left(\frac{u}{v}\right) = \frac{vu'-uv'}{v^2}

You should be able to solve this.
 
Success said:
I really don't even know how to start. I guess you should begin with yn=1/(n+1) y0.

do you mean y1 = 1/(2) y0 ?

yes you could start with that, then find y2, then y3, …

and see if you can spot a pattern :smile:
 
Success said:
I really don't even know how to start. I guess you should begin with yn=1/(n+1) y0.
IF that is true then it is the answer to your problem! If you can start writing down the answer, you surely don't need our help! How did you get that?

Poor, not so brilliant people like me might start by writing out a few values and looking for a pattern. If y_{n+1}= ((n+1)/(n+2))y_n, then y_1= ((0+1)/(0+2))y_0= y_0/2, y_2= ((1+1)/(1+2))y_1= 2y_1/3= 2(y_0/2)/3= y_0/3, y_3= ((2+1)/(2+2)y_2= (3/4)y_2= (3/4)(y_0/3)= y_0/4, y_4= ((3+1)/(3+2)y_3= (4/5)y_3= (4/5)(y_0/4)= y_0/5...

Do you think you can make a guess now? To be complete, you should then prove that your guess is correct, by induction, say.
 
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jhosamelly, I got 3/(n+2)^2 by quotient rule. How is that the answer?
 
Thanks everyone.
 
Success said:
jhosamelly, I got 3/(n+2)^2 by quotient rule. How is that the answer?
This problem has nothing to do with Calculus, the derivative, or the quotient rule.
 
  • #10
HallsofIvy said:
This problem has nothing to do with Calculus, the derivative, or the quotient rule.

Ow, sorry, I thought your title is "solve the DIFFERENTIAL equation" .
 
  • #11
spot the difference! :biggrin:
 
  • #12
jhosamelly said:
Ow, sorry, I thought your title is "solve the DIFFERENTIAL equation" .
But what you wrote had nothing to do with solving a differential equation either.
 

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