- #1

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bP = 1,0 = 1.48A + (0.72 * (1-A))

How does one solve for A in this given situation?

How does one solve for A in this given situation?

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- MHB
- Thread starter Luclucluc
- Start date

In summary, to solve for A in this given situation, expand the multiplication, combine like terms, and then divide both sides by the coefficient of A to isolate the variable. The solution for A is approximately 0.95.

- #1

- 1

- 0

bP = 1,0 = 1.48A + (0.72 * (1-A))

How does one solve for A in this given situation?

How does one solve for A in this given situation?

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- #2

Homework Helper

MHB

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Luclucluc said:bP = 1,0 = 1.48A + (0.72 * (1-A))

How does one solve for A in this given situation?

What is your equation?

Is it:

\begin{cases}

bP = 1.0 \\

1.0 = 1.48A + (0.72 * (1-A))

\end{cases}

Or is it:

\begin{cases}

bP = 1, \\

0 = 1.48A + (0.72 * (1-A))

\end{cases}

- #3

Science Advisor

Homework Helper

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Assuming that your equation is [tex]1.48A+ (0.72(1- A))= 0[/tex], first expand the multiplication: [tex]0.72(1- A)= 0.72- 0.72A[/tex].

That makes the equation [tex]1.48A+ 0.72- 0.72A= 0[/tex].

Now, combine the two "A" terms: 1.48A- 0.72A= (1.48- 0.72)A= 0.76A.

That makes the equation [tex]0.76A+ 0.72= 0[/tex].

Subtract 0.72 from both sides: [tex]0.76A= -0.72[/tex].

Finally, divide both sides by 0.76: [tex]A= -\frac{0.72}{0.76}= 0.9473[/tex]...

That makes the equation [tex]1.48A+ 0.72- 0.72A= 0[/tex].

Now, combine the two "A" terms: 1.48A- 0.72A= (1.48- 0.72)A= 0.76A.

That makes the equation [tex]0.76A+ 0.72= 0[/tex].

Subtract 0.72 from both sides: [tex]0.76A= -0.72[/tex].

Finally, divide both sides by 0.76: [tex]A= -\frac{0.72}{0.76}= 0.9473[/tex]...

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