How to stop a free-falling elevator

  • Thread starter Thread starter bfosler
  • Start date Start date
  • Tags Tags
    Elevator
Click For Summary
SUMMARY

The discussion centers on stopping a free-falling elevator with a mass of 300 kg traveling at 2.5 m/s after its cables break. The maximum allowed deceleration is 4 m/s², and the use of steel wedges and a spring mechanism is proposed to halt the descent. The analysis indicates that approximately 500 N of force is required from the spring, and the coefficient of friction between steel and the elevator shaft is 0.3. Alternative suggestions include flooding the shaft with water to mitigate injury upon impact.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of friction coefficients, specifically mu(k) for steel
  • Basic principles of mechanical springs and force calculations
  • Familiarity with elevator mechanics and safety systems
NEXT STEPS
  • Research the mechanics of spring systems in emergency braking scenarios
  • Explore advanced friction applications in mechanical systems
  • Investigate hydraulic damping systems for elevator safety
  • Learn about emergency response protocols for elevator failures
USEFUL FOR

Engineers, safety system designers, and elevator maintenance professionals seeking to enhance safety measures and emergency response strategies in elevator systems.

bfosler
Messages
1
Reaction score
0
This is a different take on an elevator problem:

An elevator and contents have a mass of 300kg and travels at 2.5 m/s during normal operation. The elevator's cables break and begins to free-fall.

You need to stop the elevator and the max allowed deceleration is 4m/s^2. There is 0.05m between each side of the elevator and the walls, and the coefficient between steel members and the elevator shaft is mu(k)=0.3.

I assume that you can use steel wedges to help stop the elevator and then couple it with a spring mechanism at the bottom. But, it seems that even with 4 steel wedges on each side, the spring will need to create a force of ~500N.

Any suggestions...because I'm kinda all out of ideas

Thanks
 
Physics news on Phys.org
It all depends on "when" you can apply your options. Is it immediately, or some?what? time before you can apply your options.

I would flood the bottom of the shaft myself. If you can get 10' of water, then you may only have a few broken legs.
 

Similar threads

Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 25 ·
Replies
25
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
3K
Replies
15
Views
32K
  • · Replies 3 ·
Replies
3
Views
11K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
2
Views
10K