How to Use Absolute Convergence Test on This Series?

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Discussion Overview

The discussion centers around the application of the absolute convergence test to the series $$\sum_{k=1}^{\infty}\left(\frac{k}{k+1}\right)^{2k}$$ and the related topic of finding the radius or interval of convergence for a function defined by a power series.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant suggests computing the limit $$L=\lim_{k\to\infty}\left(\left(\frac{k}{k+1}\right)^{2k}\right)$$ to determine the behavior of the series, noting that if $$L\ne0$$, the series must diverge, but the test is inconclusive if the limit is zero.
  • Multiple participants inquire about finding the radius or interval of convergence for the function $$f(x)=2k(x-1)^k$$, with one participant repeating the question and providing a computation for the radius of convergence as $$|x-1|<\lim_{k\to\infty}\left|\frac{2k}{2(k+1)}\right|=1$$.
  • Another participant questions the treatment of the exponent $$k$$ in the context of the radius of convergence, implying a concern about its relevance.
  • One participant responds by stating that only the coefficient of the exponential term is of concern and that constant factors in that coefficient can be disregarded.

Areas of Agreement / Disagreement

Participants express varying approaches to the absolute convergence test and the radius of convergence, with no consensus reached on the implications of the exponent or the absolute convergence test's application.

Contextual Notes

The discussion includes unresolved assumptions regarding the behavior of the series and the treatment of the exponent in the context of convergence, which may affect the conclusions drawn.

karush
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$$\sum_{k=1}^{\infty}\left(\frac{k}{k+1}\right)^{2k}$$
$\textsf{how do you use absolute converge test on this?}$
☕
 
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I think what I would do here is compute:

$$L=\lim_{k\to\infty}\left(\left(\frac{k}{k+1}\right)^{2k}\right)$$

If $L\ne0$, then the series must diverge. Bear in mind though, that this test is inconclusive if the limit of the summand is zero.
 
$\textsf{Find the radius / interval of convergence }\\$
\begin{align}
\displaystyle f(x)&=2k(x-1)^k
\end{align}
$\textsf{thot would ask another questions here since new stuff?}$
 
karush said:
$\textsf{Find the radius / interval of convergence }\\$
\begin{align}
\displaystyle f(x)&=2k(x-1)^k
\end{align}
$\textsf{thot would ask another questions here since new stuff?}$

If we are given:

$$f(x)=\sum_{k=0}^{\infty}\left(2k(x-1)^k\right)$$

Then we compute the radius of convergence as follow:

$$|x-1|<\lim_{k\to\infty}\left|\frac{2k}{2(k+1)}\right|=1$$
 
MarkFL said:
If we are given:

$$f(x)=\sum_{k=0}^{\infty}\left(2k(x-1)^k\right)$$

Then we compute the radius of convergence as follow:

$$|x-1|<\lim_{k\to\infty}\left|\frac{2k}{2(k+1)}\right|=1$$

$\text{what happened to the exponent $k$ or that a concern?}$
 
We are only concerned with the coefficient of the exponential term. In fact we can even remove any constant factors in that coefficient.
 

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