How to Write Net Ionic Equations for Na2CO3 + HCl and NaHSO4 + HCl?

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To write net ionic equations for the reactions of Na2CO3 with HCl and NaHSO4 with HCl, it's essential to recognize the dissociation of the compounds involved. Na2CO3 dissociates into Na+ and CO3^2- ions, which react with HCl to form NaCl and HCO3-, while the net ionic equation focuses on the relevant ions. For NaHSO4, it dissociates into Na+ and HSO4- ions, reacting with HCl to yield NaCl and H2SO4, with H+ ions contributing to the acidic pH. The discussion emphasizes the importance of balancing the reactions and understanding the pH changes during neutralization. Complete neutralization of Na2CO3 leads to a final pH that may vary based on the extent of the reaction.
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I have no idea how to write these two reactions as net ionic equations in order to show relevancy to their respective pH:

Na2CO3 + HCl (pH of 10.36) I know that it dissociates into OH- ions since it has a very basic pH

and

NaHSO4 + HCl (pH of 4.18) I also know that this dissociates into H+ ions since the pH is very acidic. However, I am terrible at these types of equations and desperately need help.
 
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How in the world does HCl give you a pH of 10.36?
 
Show the reaction completely as ions for the reactants and the products. Write these all fully. Then, just rewrite without all of the non-acting ions which seemed to not participate in the reaction. Note that in your first reaction you will drive ... WHAT? Why do you indicate a pH of 10.60 ? Your solution of NaCO3 might begin with that pH, but how far do you want it to go in the neutralization? All the way, or just part of the way? My guess is you want complete neutralization. Be sure you balance the reaction for this. First step is carbonate to bicarbonate; second step is bicarbonate to carbonic acid and you may lose this through decomposition to carbon dioxide.
 

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