How to Write Net Ionic Equations for Na2CO3 + HCl and NaHSO4 + HCl?

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SUMMARY

The discussion focuses on writing net ionic equations for the reactions of sodium carbonate (Na2CO3) with hydrochloric acid (HCl) and sodium bisulfate (NaHSO4) with HCl. The net ionic equation for Na2CO3 + HCl involves the dissociation of Na2CO3 into carbonate ions (CO3^2-) and hydroxide ions (OH-) in a basic solution, while HCl dissociates into H+ and Cl- ions. The reaction results in the formation of bicarbonate (HCO3-) and carbonic acid (H2CO3), which can decompose into carbon dioxide (CO2) and water. For NaHSO4 + HCl, the net ionic equation shows the dissociation of NaHSO4 into bisulfate ions (HSO4-) and H+ ions, leading to an acidic solution.

PREREQUISITES
  • Understanding of net ionic equations
  • Knowledge of acid-base reactions
  • Familiarity with pH concepts
  • Basic chemistry skills, including balancing chemical equations
NEXT STEPS
  • Study the process of writing net ionic equations for various acid-base reactions
  • Learn about the dissociation of weak acids and bases in solution
  • Explore the concept of pH and its calculation in different chemical reactions
  • Investigate the decomposition of carbonic acid and its implications in reactions
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Chemistry students, educators, and anyone seeking to understand acid-base reactions and net ionic equations in detail.

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I have no idea how to write these two reactions as net ionic equations in order to show relevancy to their respective pH:

Na2CO3 + HCl (pH of 10.36) I know that it dissociates into OH- ions since it has a very basic pH

and

NaHSO4 + HCl (pH of 4.18) I also know that this dissociates into H+ ions since the pH is very acidic. However, I am terrible at these types of equations and desperately need help.
 
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How in the world does HCl give you a pH of 10.36?
 
Show the reaction completely as ions for the reactants and the products. Write these all fully. Then, just rewrite without all of the non-acting ions which seemed to not participate in the reaction. Note that in your first reaction you will drive ... WHAT? Why do you indicate a pH of 10.60 ? Your solution of NaCO3 might begin with that pH, but how far do you want it to go in the neutralization? All the way, or just part of the way? My guess is you want complete neutralization. Be sure you balance the reaction for this. First step is carbonate to bicarbonate; second step is bicarbonate to carbonic acid and you may lose this through decomposition to carbon dioxide.
 

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