- #1
MurdocJensen
- 47
- 0
This is what I want to say:
The squeeze theorem may be used when direct substitution and factoring (or simplification of any sort) doesn't help in finding a limit.
An example would be lim x->0 of x2sin(pi/x). Limit laws wouldn't work and we can't simplify the expression. What we can do is recognize -1<= sin(pi/x)<= 1, so -(x2) <= x2sin(pi/x) <= x2. According to the squeeze theorem, if the function in question is bounded by two other function at x near a, and the lmits of these bounding functions equal each other at some a, then the limit of the bounded function also takes that value at a.
The squeeze theorem may be used when direct substitution and factoring (or simplification of any sort) doesn't help in finding a limit.
An example would be lim x->0 of x2sin(pi/x). Limit laws wouldn't work and we can't simplify the expression. What we can do is recognize -1<= sin(pi/x)<= 1, so -(x2) <= x2sin(pi/x) <= x2. According to the squeeze theorem, if the function in question is bounded by two other function at x near a, and the lmits of these bounding functions equal each other at some a, then the limit of the bounded function also takes that value at a.