How would i rearange A=2 pi r(r+h) to make h the subject?

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Discussion Overview

The discussion revolves around rearranging the equation A=2πr(r+h) to isolate h as the subject. It includes aspects of mathematical reasoning and problem-solving techniques related to algebraic manipulation.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant asks how to rearrange the equation to make h the subject.
  • Another participant suggests that to express h in terms of A, the formula would be h=(A-2πr²)/(2πr).
  • A third participant expresses uncertainty about their skills in rearranging equations.
  • A fourth participant advises that it is beneficial to show some initial work when asking for help, implying that responses may be more forthcoming with demonstrated effort.

Areas of Agreement / Disagreement

There is no clear consensus on the rearrangement process, and some participants express differing levels of confidence in their mathematical abilities.

madmike159
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How would i rearange [itex]A=2\pi r(r+h)[/itex] to make h the subject?
 
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madmike159 said:
How would i rearange A=2[tex]\pi[/tex]r(r+h) to make h the subject?

do u mean to express it in terms of h??
then [tex]\ h=\frac{A-2^{pi}r^{2}}{2^{pi}r}[/tex]
 
I think it means the same thing. Thanks, I'm really bad at rearranging
 
well, next time try to show some work of yours first. Because the people here won't just give u the answer unless u have given some thought to the problem.
 

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