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Hypergeometric distribution

  1. Apr 1, 2007 #1
    Hello,
    Im just wondering is there a simply calculated formula for the expected value and variance for the hypergeometric distribution. I know how to do it with long calculations. I know the expected value for the binomial is = np and the variance is = npq = np(1-p) .. Is there something like this for the hyper.. I lost my good stats book so im not sure..
    thanks
    adam
     
  2. jcsd
  3. Apr 1, 2007 #2

    HallsofIvy

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