Hypergeometric distribution

  • Thread starter Pearce_09
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Hello,
Im just wondering is there a simply calculated formula for the expected value and variance for the hypergeometric distribution. I know how to do it with long calculations. I know the expected value for the binomial is = np and the variance is = npq = np(1-p) .. Is there something like this for the hyper.. I lost my good stats book so im not sure..
thanks
adam
 

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