, I don't have a clue how to calculate this.

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The discussion revolves around calculating the effective force exerted by a piston on a crankshaft, particularly in the context of a mechanical system involving levers and cams. The original poster expresses confusion about how to determine the force contributing to crank rotation versus that which could cause damage. Participants clarify that while the torque on the crankshaft varies throughout its cycle due to changing geometry, there is no inherent loss of power from the sideways force of the piston, aside from minor frictional losses. They emphasize the importance of understanding mechanical advantage and torque fluctuations, especially when designing systems like reciprocating pumps and compressors. The conversation highlights the complexity of force analysis in mechanical systems, particularly when friction is considered.
  • #31
No worries.
The torque is about the center of the crank. This is inclusive of the 5.25" moment arm.
Basically you can think of it as 164 lbf acting perpendicular to the crank arm at that 5.25" distance.
 
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  • #32
FeX32 said:
No worries.
The torque is about the center of the crank. This is inclusive of the 5.25" moment arm.
Basically you can think of it as 164 lbf acting perpendicular to the crank arm at that 5.25" distance.

FeX32,

That is what I thought it was, I did get that number as well as at the cam I believe it's 328 lbf. This is better than I had hoped for in this application.

It is the final answer I needed and I've worked on this machine for the better part of 6 years. I have tried to figure it many ways, never was sure of the outcome tho! Now I fully believe it will work. I had little doubt ;)!

Thank You Again! I won't forget your help!

ed
 
  • #33
You're welcome ed. Good luck with your machine.
All the best to ya,
 

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