MHB I don't understand the question.

[Alone]

This is a simple question.

On pages 5-6 of Measure Theory,Vol 1, Vladimir Bogachev he writes that:

for E=(A\cap S)\cup (B\cap (X-S))

Now, he writes that:

X-E = ((X-A)\cap S) \cup ((X-B)\cap (X-S))

But I don't get this expression, I get another term of ((X-B)\cap (X-A))

i.e, X-E =( ((X-A)\cap S) \cup ((X-B)\cap (X-S)))\cup ((X-B)\cap (X-A)).

I believe I did it correctly according to De-Morgan rules and distribution.

I am puzzled...

 

[Alone]

Re: Something in Measure Theory.

Nevermind, I got it.

It follows from the fact that S is disjoint to A and B.

Sometimes I wonder how I still can do math...:-D