I have a problem finding the permitivity of acetate, can some one help me

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SUMMARY

The discussion centers on calculating the permittivity (ε) of acetate used in a capacitor setup. Given the dielectric constant (k) of acetate as 3.4, the formula ε = k * ε₀ is applied, where ε₀ (the permittivity of vacuum) is approximately 8.85 x 10⁻¹² F/m. Thus, the permittivity of acetate is determined to be approximately 3.0 x 10⁻¹¹ F/m. This calculation is essential for understanding the behavior of capacitors in electronic circuits.

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Homework Statement


The question goes as follows: A simple capacitor consists of two square sheets of aluminium foil separated by a thin sheet of acetate. The foil is 31.6 cm on a side and the acetate is 0.5 cm thick, with a dielectric constant k= 3.4

What is the permittivity ε of the acetate sheet?

Homework Equations


q= CV C=kε(knot)A/d
 
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How is the dielectric constant defined in terms of permittivity of the material and permittivity of vacuum?

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