I have a Wronskian Question?If the Wronskian W of f and g is t^2*e^t

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The Wronskian W of functions f and g is defined as W = t^2 * e^t. Given f(t) = t, the task is to find g(t). The correct approach involves setting up the equation tg' - t'g = t^2 * e^t and utilizing the integrating factor µ = e^-t. The solution yields g(t) = te^t + c, where c is a constant, confirming that the quotient rule is essential in this derivation.

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I have a Wronskian Question?
If the Wronskian W of f and g is t^2*e^t and if f(t)=t, find g(t).

I have tried setting up this problem:

tg'-t'g = t^2*e^t
tg'-g = t^2*e^t

Setting up the integrating factor, µ= e^∫-1 --> µ= e^-t
(e^-t)t*g' - (e^-t)*g = (e^-t)(t^2*e^t)

so preferably I would want to be able to set up the equation as (fg)' = (e^-t)(t^2*e^t)

but the derivative of (e^-t)t is not (e^-t).

The answer is supposed to be te^t+ct
 
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The quotient rule is handy here
f g'-f' g=f2(g/f)'

f g'-f' g=t2(g/t)'=t2et
 


I'm still not getting the right answer.

I get it down to (te^t)(t-1)+ct
 


Where are you getting that t-1? It clearly does not belong.
 

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