# I honestly cannot believe I am stuck on this.

#### flyingpig

1. The problem statement, all variables and given/known data

Solve

$$\left | \frac{5}{x + 2} \right | < 1$$

3. The attempt at a solution

All I know is that x= -2 is discontinuous. I thought about doing test points, but it seemed rather useless seeing I will probably end up with (-2, infinity) or (-inf, -2)

Computer says the solution is x < -7, x >3

I then thought about doing this

$$\left |5\right | < \left|x + 2\right|$$
$$-|x + 2| < -5$$
$$5 < -(x + 2) < -5$$
$$-5 > x + 2 > 5$$
$$-7 > x > 3$$

I am sorry lol

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#### Saitama

I don't understand how you get the third step?

You should go by taking two cases.
What do get when you solve |x+2|? Definitely (x+2) and -(x+2).

If you solve these two equations:-
5<(x+2)
and
5<-(x+2)
You will get the desired result.

#### BloodyFrozen

$$-7 > x > 3$$

?????????????????????????????????????????

x is greater than 3 and less than -7?

#### flyingpig

See I don't know what I am doing lol

Gold Member
See I don't know what I am doing lol
You can set up two inequalities (see Pranav-Anora's post). Or you can set up a double inequality since this problem is of the "less-than" variety. You attempted to do the double inequality method, but you shouldn't have a negative on your absolute value expression. I think you mixed two different methods into one.

Here's a general example of how you should've setup the double inequality:

Given |expression| < k, set up the double inequality, -k < |expression| < k and solve.

#### uart

See I don't know what I am doing lol
Why don't you try making a sketch of y= |5/(x+2)| and y=1 on the same set of axes.

#### Mark44

Mentor
Solve

$$\left | \frac{5}{x + 2} \right | < 1$$

3. The attempt at a solution

All I know is that x= -2 is discontinuous.
No, the rational expression is undefined at x = -2.
I then thought about doing this

$$\left |5\right | < \left|x + 2\right|$$
|x + 2| > 5 and x $\neq$ -2

In general, if you have an inequality of the form |x + a| > b, you can get rid of the absolute values by rewriting this as
x + a > b or x + a < - b

For your problem, since x cannot be -2, any interval you end up with cannot include -2.

#### Ray Vickson

Homework Helper
Dearly Missed
1. The problem statement, all variables and given/known data

Solve

$$\left | \frac{5}{x + 2} \right | < 1$$

3. The attempt at a solution

All I know is that x= -2 is discontinuous. I thought about doing test points, but it seemed rather useless seeing I will probably end up with (-2, infinity) or (-inf, -2)

Computer says the solution is x < -7, x >3

I then thought about doing this

$$\left |5\right | < \left|x + 2\right|$$
$$-|x + 2| < -5$$
$$5 < -(x + 2) < -5$$
$$-5 > x + 2 > 5$$
$$-7 > x > 3$$

I am sorry lol
For real A, the inequality |A| < 1 is the same as -1 < A < 1.

RGV

#### NascentOxygen

Mentor
Last edited by a moderator:

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