I Really Need Help Chemistry: Synthesis of a Coordination Compound

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SUMMARY

The discussion centers on the synthesis of the coordination compound K3[Fe(C2O4)3].3H2O using ferrous ammonium sulfate (FAS) as the limiting reagent. The theoretical yield of K3[Fe(C2O4)3].3H2O is calculated to be 5.01 grams, resulting in a percent yield of 50.7% based on an actual yield of 2.54 grams. The oxidation state of the central metal ion, iron (Fe), is determined to be +3, and the coordination number is identified as 6. The discussion emphasizes the importance of stoichiometry and molar ratios in calculating yields.

PREREQUISITES
  • Understanding of stoichiometry and molar calculations
  • Familiarity with coordination compounds and their properties
  • Knowledge of chemical equations and balancing reactions
  • Basic grasp of oxidation states and coordination numbers
NEXT STEPS
  • Study stoichiometry in detail, focusing on limiting reagents and theoretical yields
  • Learn about coordination chemistry, specifically the properties of coordination compounds
  • Explore the concept of oxidation states and how to determine them in complex ions
  • Investigate the significance of coordination numbers in chemical bonding
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Chemistry students, particularly those studying coordination compounds, synthetic chemistry, and stoichiometry. This discussion is beneficial for anyone looking to enhance their understanding of chemical yields and reaction mechanisms.

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Homework Statement



Mass of Ferrous Ammonium Sulfate (limiting reagent) = 4.00 grams.

Mass of K3[Fe(C2O4)3].3H2O = 2.54 grams.


QUESTIONS:

1. Using the above mass of ferrous ammonium sulfate calculate the theoretical yield of the K3[Fe(C2O4)3].3H2O
2. What is the percent (%) yield of the K3[Fe(C2O4)3].3H2O
3. Draw the shape of the complex ion {I have this one already...thanks! :)}
4. What is the oxidation state of the central metal ion?
5. What is the coordination number of the central metal ion?

Homework Equations



(1) FeSO4.(NH4)2SO4.6H2O + H2C2O4.2H2O --> FeC2O4 + (NH4)2SO4 + H2SO4 + 8H2O

(2) 6FeC2O4 + 3H2O2 + 6K2C2O4.H20 --> 4K3[Fe(C2O4)3].3H20 + 2Fe(OH)3
+ 6H20

(3) 2Fe(OH)3 + 3H2C2O4.2H2O + 3K2C2O4.H2O --> 2K3[Fe(C2O4)3].3H2O + 9H2O


The Attempt at a Solution



O.k...I really have NO idea how to do this but here is what I think...
I understand that it's about stoichiometry, recognizing which reactant is the limiting reagent
and then calculating the moles of that reactant and then developing molar ratios. Then, when I have calculated my theoretical yield I could divide my actual yield by it and then multiply by 100 and get my percent yield. The problem is that the equations look long and complex and I'm intimidated. Also, I would have no clue as to the remaining questions. This assignment is worth a lot for me so any help anyone could offer me would be TRULY and GREATLY appreciated, thanks! :)
 
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You are close. You don't have to recognize limiting reactant - you are already told which one it is. Try to approach it just looking at the number of moles of important reactants - that is, you start with x moles of Fe, how many moles of the final product can you produce? It is enough to count Fe atoms to get the idea.

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Hello,

Thank you for your reply. Here is my attempt...

So... ferrous ammonium sulfate = FAS & potassium trioxalatoferrate = PTOF

(1) 4.00 g FAS x (1 mol FAS / 392.14088 g ) = 0.010200415 mol of FAS.


0.010200415 mol FAS x (1 mol PTOF / 1 mol FAS) = 0.010200415 mol of PTOF

0.010200415 mol PTOF x (491.24274 g / 1 mol PTOF) = 5.01 g PTOF {theoretical yield}

(2) (2.54 g PTOF / 5.01 g PTOF) x 100 = 50.7 % {percent yiel}


(3) Got it.


(4) The central metal ion I believe would be iron (Fe) and it's oxidation state I think it would be +3?

(5) I'm not entirely sure as to what a coordination number is but as far as I know it's the number of atoms the atom in question is bonded to...? In this case I think it would be 6?

So far, is this correct? Thank for your time!
 
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