B I wonder about a particle's energy when mass is obtained or lost

seonjunyoo
Messages
5
Reaction score
1
According to Einstein's formula, energy is generated when mass is obtained or lost.

What does losing or gaining mass mean for an atom or particle valence?
It's simply because of the formula I don't want this kind of answer
I want. What does it mean for an atom or particle to lose or gain mass from the perspective of an atom or particle?

Along with What does mass mean for an atom or particle?
If you don't understand the question, I'm sorry. My English is not my first language
 
Physics news on Phys.org
The energy is not generated, it is just converted from one type to another.
seonjunyoo said:
What does it mean for an atom or particle to lose or gain mass from the perspective of an atom or particle?
The mass changes. What is unclear?

As an example, a hydrogen atom has a slightly smaller mass than the sum of a proton mass plus an electron mass.
 
  • Like
Likes dextercioby
seonjunyoo said:
According to Einstein's formula, energy is generated when mass is obtained or lost.
I don't know if this is what you are referring to, but are you familiar with Nuclear Binding Energy?

1714065008815.png

https://en.wikipedia.org/wiki/Nuclear_binding_energy
 
Thread 'Why is there such a difference between the total cross-section data? (simulation vs. experiment)'
Well, I'm simulating a neutron-proton scattering phase shift. The equation that I solve numerically is the Phase function method and is $$ \frac{d}{dr}[\delta_{i+1}] = \frac{2\mu}{\hbar^2}\frac{V(r)}{k^2}\sin(kr + \delta_i)$$ ##\delta_i## is the phase shift for triplet and singlet state, ##\mu## is the reduced mass for neutron-proton, ##k=\sqrt{2\mu E_{cm}/\hbar^2}## is the wave number and ##V(r)## is the potential of interaction like Yukawa, Wood-Saxon, Square well potential, etc. I first...
Back
Top