Kc = 4.15 x 10-2 at 356°C for PCl5(g) ↔ PCl3(g) + Cl2(g). A closed 2.00 L vessel initially contians 0.100 mol PCl5. Calculate the total pressure in the vessel (in atm to 2 decimal places) at 356°C when equilibrium is achieved.
Kp= Kc(RT)^change in n
Kp= Pressure products/pressure reactants
Small x approximation
The Attempt at a Solution
The answer key says 4.09 for Ptotal, but I keep getting a wrong answer