Identical particles/ Time dependent perturbation theory

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SUMMARY

The discussion centers on the interaction of two identical spin-1/2 particles governed by the Hamiltonian H0=ω0 S1·S2 and a time-dependent perturbation H'=ω1 (S1z-S2z) θ(t) Exp[-t/τ]. The primary focus is on calculating the probabilities of transitioning from the ground state to excited states using first-order perturbation theory. The participants clarify that due to the indistinguishability of identical fermions, only anti-symmetric states are permissible, leading to confusion regarding the probabilities of transitions between states. The conclusion emphasizes the necessity of considering the symmetry properties of the wavefunction in the context of identical particles.

PREREQUISITES
  • Understanding of quantum mechanics, specifically spin-1/2 particles.
  • Familiarity with perturbation theory in quantum mechanics.
  • Knowledge of Hamiltonians and their role in quantum systems.
  • Concept of indistinguishable particles and anti-symmetrization in quantum states.
NEXT STEPS
  • Study the principles of time-dependent perturbation theory in quantum mechanics.
  • Learn about the properties of identical fermions and the implications of the Pauli exclusion principle.
  • Explore the Ising model and its applications in spin interactions in condensed matter physics.
  • Investigate the mathematical formulation of coupled basis states for identical particles.
USEFUL FOR

Quantum physicists, graduate students in physics, and researchers working on quantum mechanics and particle interactions will benefit from this discussion.

dreinh
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Homework Statement


Two identical spin-1/2 particles interact with Hamiltonian H0=ω0 S1.S2 where ω0>0. A time dependent perturbation is applied, H'=ω1 (S1z-S2z) θ(t) Exp[-t/τ], where ω1>0 and ω1<<ω0. What are the probabilities that a system starting in the ground state will be excited into each of the three excited states to first order?

Homework Equations


P[initial state -> final state] = Norm[ Integrate[ < final l H'[t'] l initial > Exp[ I (Ef - Ei) t'], {t',0,t}]]^2

The Attempt at a Solution



Sorry if the statement is unclear, but I just wanted to make sure my thinking on this is correct. We have two identical fermions interacting through a spin-spin interaction, so the first thing to do in my head is to use the coupled basis states representing the particles. We only have spin interactions so spatial states aren't needed. In a non-identical particle situation, we would have four possible states:

l 1 1 > = l + +>
l 1 0 > = 1/Sqrt[2] (l + - > + l - + >)
l 0 0 > = 1/Sqrt[2] (l + - > - l - + >)
l 1 -1 > = l - - >

But since we have two identical spin-1/2 particles, only the anti-symmetric state is allowed, so our initial state must be the l 0 0 > state.

Now here is where I get confused. Our perturbation Hamiltonian is still only dependent on spin interactions, so our final state should still be one of the four kets listed above. If this is the case I don't see why all probabilities aren't zero (besides the l0 0> -> l0 0> probability) since we can't find fermions in a symmetric state. For all I know this is a trick question and I could be thinking correctly about it, but I feel like there should be some sort of computation that goes along with this.
 
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Why do the particles have to have the same spatial wavefunction? (This would be what restricts the system to be in the singlet state.) Is this stated in the problem? An example of a typical spin-spin interaction which gives the Hamiltonian you supplied might be that between two electrons on neighboring lattice sites in a ferromagnetic crystal (c.f. Ising model). There is no reason why the system could not be in any of the four possible states.
 

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