Identification of group 2 metal salts

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SUMMARY

The discussion focuses on the identification of unknown group 2 metal salts, labeled as X and Y, through various chemical tests. When dilute NaOH was added, Y formed a precipitate while X turned colorless, indicating that Y likely contains an ion that is insoluble in hydroxide, such as magnesium or beryllium. Additional tests with AgNO3 and BaCl2 were suggested to identify anions present in the salts. The participants concluded that further information is necessary to accurately identify the salts, particularly regarding their solubility and the specific concentrations of the reagents used.

PREREQUISITES
  • Understanding of group 2 metal chemistry
  • Knowledge of precipitation reactions
  • Familiarity with common laboratory reagents like NaOH, AgNO3, and BaCl2
  • Basic skills in interpreting chemical reactions and solubility rules
NEXT STEPS
  • Research the solubility rules for group 2 metal hydroxides and their behavior in alkaline solutions
  • Learn about the qualitative analysis of anions using AgNO3 and BaCl2
  • Investigate the properties of specific group 2 salts, such as magnesium chloride and barium sulfate
  • Explore the concept of complex ion formation in relation to group 2 metals
USEFUL FOR

Chemistry students, laboratory technicians, and educators involved in chemical analysis and identification of metal salts.

david18
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Hi, I carried out a couple of experiments with unknown group 2 salts; X and Y

I added dilute NaOH to each of the salts which were now mixed with 1cm^3 of water; Y formed a precipitate (initially the solution was colourless as the solute had dissolved) whilst X turned colourless (X's solution was initially insoluble and was therefore a ppt before)
What conclusions could I draw from these observations? I think it might have something to do with Y having an ion that is insoluble when added to OH (ie Be and Mg) and vice versa... but I am not too sure...

Another test was adding AgNO3 + nitric acid, and in another I added BaCl2 - what could these show me?
 
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david18 said:
Hi, I carried out a couple of experiments with unknown group 2 salts; X and Y

I added dilute NaOH to each of the salts which were now mixed with 1cm^3 of water; Y formed a precipitate (initially the solution was colourless as the solute had dissolved) whilst X turned colourless (X's solution was initially insoluble and was therefore a ppt before)
What conclusions could I draw from these observations? I think it might have something to do with Y having an ion that is insoluble when added to OH (ie Be and Mg) and vice versa... but I am not too sure...

Another test was adding AgNO3 + nitric acid, and in another I added BaCl2 - what could these show me?
Very difficult question with only these data.

1. X and Y are necessarily salts or can also be oxides/idroxydes?
2. group 2 include also 2b, that is Zn, Cd, Hg?
3. How dilute is NaOH? Can you specify better the concentration or the pH of the solution?

About substance X: an insoluble group 2 salt that dissolves with diluted NaOH, have I understood correctly?

Berillium idroxyde, carbonate, phosphate are insoluble but dissolves in high alcaline solutions ( not very diluted, then). The same with Zinc, for example.

About Y, there are many elements and many salts for every of those elements which dissolve in water and precipitates with OH-:

Mg (alogenides, nitrate, sulfate), Ca (alogenides, nitrate), Cd (alogenides, nitrate, sulfate), Hg (Hg(II) alogenides, nitrate).

Be and Zn precipitates with diluted sol. of OH- and re-dissolves in high con. of OH-.
 
AgNO3 will help you to find out if there are halide ions (chloride, iodide, bromide,..) in the salts X and Y.

BaCl2 will tell you if sulphate is present.

These two tests determine the anions.

the test with NaOH will help to distinguish the cation.
and i think Y is MgCl2 or MgSO4. you will know that when you test the anion. A white ppt. is formed when you add the Mg salt to NaOH.

This appears to be a school lab experiment. simple and easily available reagents are involved.
 
Last edited:
Kushal said:
i think X is BaSO4. BaSO4 is insoluble in water, but when you add NaOH, it dissolves.
I don't think so. Which should be the reaction?
 
o yeah, of course, X is NOT BaSO4, i will correct that right here. i think more information is required. sorry
 

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