Identifying Discontinuities in a Function on a Given Interval

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SUMMARY

The discussion centers on identifying discontinuities in the function F(X) = (X^2 - 2x + 1)^(1/3) over the interval [-4, 4]. Participants emphasize the importance of correctly graphing the function to locate points of non-differentiability. The confusion arises from the interpretation of the interval endpoints and whether the graph must touch these points to be considered continuous. Ultimately, the key takeaway is that a function can be continuous on an interval even if it does not touch the endpoints.

PREREQUISITES
  • Understanding of function continuity and differentiability
  • Familiarity with graphing techniques for polynomial and radical functions
  • Basic knowledge of calculus concepts related to limits and derivatives
  • Experience using graphing calculators or software
NEXT STEPS
  • Learn how to graph functions using Desmos or GeoGebra
  • Study the properties of continuity and differentiability in calculus
  • Explore the concept of limits to understand points of discontinuity
  • Investigate the implications of endpoints in interval notation
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Students studying calculus, particularly those focusing on continuity and differentiability, as well as educators seeking to clarify these concepts for their learners.

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Homework Statement


Grapher: Graph each function on (-4,4), and identify the point(s) at which the function is not differentiable.



Homework Equations


Graph F(X) = (X^2-2x+1)^1/3 on [4,-4] and Identify any points of discontinuity.



The Attempt at a Solution


I plugged in the F(x) equation on my calculator and I don't how to graph it on [-4,4]? I tried tracing the F(X) graph but I don't see the graph hitting the pt [-4.4] anywhere, am I doing this wrong?
 
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Another thing after thinking about it a bit more, when it says Graph it on [-4,4] does it mean that the F(x) equation has to to touch that point? If it does its continous? If it doesn't it does not exist?
 

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