If You Know What I Mean's question at Yahoo Answers regarding summations

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SUMMARY

This discussion addresses the calculation of the sum of integers between 0 and 101 that are divisible by 2 and 5. The formula used is the summation of sequential natural numbers, specifically $$\sum_{k=1}^nk=\frac{n(n+1)}{2}$$. For integers divisible by 2, the sum is calculated as 2550, while for those divisible by 5, the sum is 1050. The calculations are based on the upper limit determined by $$\left\lfloor\frac{101}{m} \right\rfloor$$, where m is the divisor.

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MarkFL
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Here is the question:

How with sequence question?

find the sum of all integers between 0 an 101 that are divisible by a)2 b)5

thanks

Here is a link to the question:

How with sequence question? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.
 
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Hello If You Know What I Mean,

For these two questions, we will rely on the formula:

$$\sum_{k=1}^nk=\frac{n(n+1)}{2}$$

We will factor out the integer $m$ which divides each term, leaving a summation of sequential natural numbers, whose upper limit of summation is determined by $$\left\lfloor\frac{101}{m} \right\rfloor$$. Hence, we find:

a) $$S=2\sum_{k=1}^{50}k=2\cdot\frac{50(50+1)}{2}=50 \cdot51=2550$$

b) $$S=5\sum_{k=1}^{20}k=5\cdot\frac{20(20+1)}{2}=50 \cdot21=1050$$

To If You Know What I Mean and any other guests viewing this topic, I invite and encourage you to post other summation of arithmetic series questions in our http://www.mathhelpboards.com/f2/ forum.

Best Regards,

Mark.
 

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