1. Jan 18, 2006

Robby11

A ball is dropped from rest a height h above the ground. Another ball is thrown vertically upward from the ground at the instant the first ball is released. Determine the speed of the second ball if the two balls are to meet at a height h/2 above the ground.

Ive been working so long on homework today maybe thats the reason I cant figure this one out...can someone please help me Thankyou

2. Jan 18, 2006

Mindscrape

What have you done so far?

3. Jan 18, 2006

Robby11

For the ball released from height h, h/2 = 1/2gt^2, where t is the time taken to fall a distance of h/2. Therefore t = (h/g)^1/2.........i have no clue where to go next or if this is even correct

Last edited: Jan 18, 2006
4. Jan 18, 2006

Mindscrape

You can almost intuitively even figure this one out. You seem to be off to a good start though. Also, remember that you know that the time is the same for both since they meet at the same time.