Im not sure if this is the correct formula for this question, corect me

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SUMMARY

The discussion centers on calculating the distance traveled by a toy rocket during its acceleration from 12 m/s to 40 m/s over a period of 5 seconds. Participants confirm that the change in velocity (Δv) is calculated as 40 m/s - 12 m/s, resulting in Δv = 28 m/s. The equation Δt = Δv/a is utilized, where acceleration (a) is derived from the change in velocity over time. The correct interpretation of the problem indicates that the rocket has already been moving for 5 seconds, and the distance traveled can be calculated using the appropriate kinematic equations.

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Im not sure if this is the correct formula for this question, please corect me

Homework Statement


hi this is the problem: the burning of the second stage of a two stage toy rocket takes the rocket from 12 m/s to 40 m/s in 5.0s. How far does the rocket during this time?


Homework Equations


would i use delta t= delta v/a ?
 
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Yes, you would need to use that equation.
 
Thanks neutrino.. but would i do (40-12) to find the velcoity?
 
What are the 'knowns' in \Delta t = \frac{\Delta v}{a}? Substitute them and find the unknown.
 
the knowns are velocity and acceleration, yeah i know that you substitute them but would i do (40-12) to find the velcoity?
so like for (40-12) do i plug that in velocity together?
 
Last edited:
ImsoFly said:
the knowns are velocity and acceleration

Are you sure about that?

Delta v is change in velocity = Final velocity - Initial Velocity = 40-12.
 
neutrino said:
Are you sure about that?

Delta v is change in velocity = Final velocity - Initial Velocity = 40-12.

Yeah, so it's 23 but i was just saying...how would i put that in the formula in the proper way...

delta t= delta v/a, delta t= (40-12)/5.0s, delta t =28m/s /5.0s = 5.6s
therefore the rocket traveled for 5.6 s?
 
ImsoFly said:
delta t= delta v/a, delta t= (40-12)/5.0s, delta t =28m/s /5.0s = 5.6s
therefore the rocket traveled for 5.6 s?

Units are important physics, and the Second is a unit of time.

It has already been stated in the problem that the rocket has been moving for 5 seconds when it's speed changed from 12 to 40 m/s. Acceleration is a measure of how velocity changes with time.
 
neutrino said:
Units are important physics, and the Second is a unit of time.

It has already been stated in the problem that the rocket has been moving for 5 seconds when it's speed changed from 12 to 40 m/s. Acceleration is a measure of how velocity changes with time.

Okay...thanks for taking your time :rolleyes:
 

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