Probability per atom and per second for stimulated emission to occur

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Homework Help Overview

The discussion revolves around calculating the probability per atom and second for stimulated emission in a hydrogen plasma at a temperature of 4500 ºC, specifically from the 2p to 1s energy state. The original poster mentions a lifetime of 1.6 ns for the 2p state and seeks guidance on the relevant formulas and approaches to take.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the lifetime of the excited state and the probability of stimulated emission, with one participant calculating a value for A based on the lifetime. There is also discussion about the dependence of stimulated emission probability on radiation density and temperature, referencing Planck’s radiation law. Questions arise regarding the necessary quantities to calculate A, such as B and ΔE.

Discussion Status

The discussion is active, with participants providing insights and attempting to connect various concepts. Some guidance has been offered regarding the use of the lifetime and the relationship between radiation density and temperature. However, there is no explicit consensus on the next steps or the required quantities for the calculations.

Contextual Notes

Participants note the lack of certain quantities, such as B and ΔE, which are necessary for completing the calculations. The original poster is working within the constraints of the problem as posed, without additional information on these parameters.

Philip Land
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Homework Statement


We are investigating hydrogen in a plasma with the temperature 4500 ºC. Calculate the probability per atom and second for stimulated emission from 2p to 1s if the lifetime of 2p is 1.6 ns

Homework Equations


##A=\frac{1}{\Sigma \tau}##

$$A_{2,1} = \frac{8*\pi *h * f^3*B_{2,1}}{c^3}$$

The Attempt at a Solution


[/B]
hmmm, I'm not sure how to approach this problem. I took the inverse of the life time and got that A= ##6.25*10^8 S^{-1}.##

But I'm not sure where to start or what formulas to use.

The only formula I know of which takes temperature into account is
Doppler line width: ##\Delta F = constant * f_0 * \sqrt(T/M) ## which I can't see how to apply in this case at all.

Any input on where to start?
 
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The probability of stimulated emission will depend on the density of radiation around the atom, which depends on the temperature.
 
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mfb said:
The probability of stimulated emission will depend on the density of radiation around the atom, which depends on the temperature.
Thanks a lot! I manage to as you said find a relation between radiation density and temperature, (Planck’s radiation law).

Then I used a Radiation balance and solved for ##A_{21} = \rho (f) * \frac{N_1}{N_2}*B_{12}
-B{21}*\rho (f). ##

Where ##g_1*B_{12} = g_2*B_{21}## if we let g1=g2 we get ##B_{12}=B_{21}##

We also know from statistics that ##\frac{N_1}{N_2}= e^\frac{- \Delta E}{kT}##

But my question is. To get A (which I guess I'm supposed to get). I need B and ##\Delta E## But I don't have those quantities... (as I'm aware of).
 
Did you use the given lifetime already?
 
mfb said:
Did you use the given lifetime already?
Yes I used that to get the frequency, used in Plancks radiation law.
 
Philip Land said:
##A_{21} = \rho (f) * \frac{N_1}{N_2}*B_{12} -B{21}*\rho (f). ##
It might help to rearrange this equation as ##N_2A_{21} + N_2B_{21}\rho (f)= N_1B_{12}\rho (f) ##.
Interpret each of the terms. One of the terms is closely related to what you are asked to find.
 

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