I'm stuck on a proof that's probably trivial, any insights?

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SUMMARY

The discussion centers on proving that the sum of the polynomial P(a,b,c,d,e,f...x) when acted upon by the symmetric group of order n, multiplied by the sign function, equals the Vandermonde determinant of the variables. Participants clarify the use of the standard definition of determinants, including co-factor expansion and the sign function. They reference the Vandermonde matrix properties and confirm that the identity being proven is a specific case of a more general determinant identity. Key resources include Wikipedia articles on determinants and class notes detailing the permutation approach to determinants.

PREREQUISITES
  • Understanding of polynomial functions and their properties
  • Familiarity with the symmetric group and its operations
  • Knowledge of determinants, particularly the Vandermonde determinant
  • Experience with co-factor expansion in matrix algebra
NEXT STEPS
  • Study the properties of the Vandermonde matrix in detail
  • Learn about the sign function and its role in determinant calculations
  • Review the permutation approach to determinants as outlined in the provided class notes
  • Explore advanced topics in polynomial algebra and symmetric functions
USEFUL FOR

Mathematicians, students studying linear algebra, and anyone interested in advanced polynomial identities and determinants will benefit from this discussion.

PsychonautQQ
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Given polynomial P(a,b,c,d,e,f...n) = (a^0)(b^1)(c^2)...(n^n)

show that the sum of P(a,b,c,d,e,f...x) when acted upon by the symmetric group of order n and each time multipled by the sgn function (1 if even and -1 if odd); that this sum is equal to the vandermonde determinant of these variables. Any insights? I'm quite lost.
 
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What is your definition of the determinant? Do you know of the definition which uses the sign function?
 
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Well, I believe that I'm using the standard definition for the determinant of the matrix (the resulting polynomial from co-factor expansion). However, the resulting determinant from a vandermonde matrix can be given by a simpler formula; it's given on this page under 'properties' https://en.wikipedia.org/wiki/Vandermonde_matrix.
 
So yes, I'm using the definition that involves the sign function. I'm still having trouble getting from the sum of alternating polynomials acted on by the symmetric group and the definition of the determinant of the vandermonde matrix.
 
Wow, so this is like exactly what I'm looking for?
 
Yep!
 
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u da boss :D
 
So just to clarify, what you're saying is that the map that I'm trying to prove is equivalent to the vandermonde determinant is really equivalent to determinants in general, and thus equivalent to the vandermonde determinant.
 
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Yes. The identity you are trying to prove is a special case of a more general identity.
 
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If you want to go through the details of this standard permutation approach to determinants, including the proof that it agrees with the expansion by rows you mention, it is explained on pages 62-67 of these class notes:

http://alpha.math.uga.edu/%7Eroy/4050sum08.pdf
 
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