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**[SOLVED] Impulse and Momentum problem on skaters**

## Homework Statement

A 50.0-kg skater is traveling due east at a speed of 3.00 m/s. A 70.0-kg skater is moving due south at a speed of 7.00 m/s. They collide and hold on to each other after the collision, managing to move off at an angle

*theta*south of east, with a speed of

*v(f)*. Find (a) the angle

*theta*and (b) the speed

*v(f)*, assuming that friction can be ignored.

## Homework Equations

Tangent of

Momentum = mass * volume

## The Attempt at a Solution

I first decided to find the angle

*theta*. I drew a picture on a separate sheet of paper (sorry, I don't have a way of posting an image here, but it should be easy to reproduce) to make the problem look easier. I used

*tan theta*=(opposite/adjacent) but I got 66.8 degrees as my answer with 7 as the opposite and 3 as the adjacent, whereas my answer booklet says 73.0 degrees. I thought velocities could be treated as vectors.

Also, for part b, the answer is 4.28 m/s, but I also don't know how to get this answer. I thought I could use the pythagorean theorem, but that doesn't work. It seems like I'm missing some vital concepts here. Any help would be appreciated.

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