[SOLVED] Impulse and Momentum problem on skaters 1. The problem statement, all variables and given/known data A 50.0-kg skater is traveling due east at a speed of 3.00 m/s. A 70.0-kg skater is moving due south at a speed of 7.00 m/s. They collide and hold on to each other after the collision, managing to move off at an angle theta south of east, with a speed of v(f). Find (a) the angle theta and (b) the speed v(f), assuming that friction can be ignored. 2. Relevant equations Tangent of Momentum = mass * volume 3. The attempt at a solution I first decided to find the angle theta. I drew a picture on a separate sheet of paper (sorry, I don't have a way of posting an image here, but it should be easy to reproduce) to make the problem look easier. I used tan theta=(opposite/adjacent) but I got 66.8 degrees as my answer with 7 as the opposite and 3 as the adjacent, whereas my answer booklet says 73.0 degrees. I thought velocities could be treated as vectors. Also, for part b, the answer is 4.28 m/s, but I also don't know how to get this answer. I thought I could use the pythagorean theorem, but that doesn't work. It seems like I'm missing some vital concepts here. Any help would be appreciated.