Impulse with snowballs hitting a wall

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Homework Help Overview

The discussion revolves around calculating impulse and average force related to snowballs impacting a wall. The problem involves a steady stream of snowballs, their mass, impact velocity, and the resulting forces depicted in a graph.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the calculation of impulse using the average force and time, questioning the sign of the impulse based on the perspective of the wall versus the snowball. They also discuss methods for determining average force from the graph of isosceles triangles and the relationship between force, mass, and velocity.

Discussion Status

Some participants have provided calculations and interpretations of the problem, while others have raised questions about the completeness of the given data and the implications of the calculations. There is an acknowledgment of the correctness of some approaches, but no consensus has been reached on all aspects of the problem.

Contextual Notes

Participants note the absence of specific numerical values for impact velocity, duration, and separation time in the original post, which may affect the clarity of the discussion.

Jrlinton
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Homework Statement


Two average forces. A steady stream of 0.250 kg snowballs is shot perpendicularly into a wall at a speed of . Each ball sticks to the wall. Figure 9-49 gives the magnitude F of the force on the wall as a function of time t for two of the snowball impacts. Impacts occur with a repetition time interval , last a duration time interval , and produce isosceles triangles on the graph, with each impact reaching a force maximum . During each impact, what are the magnitudes of (a) the impulse and (b) the average force on the wall? (c) During a time interval of many impacts, what is the magnitude of the average force on the wall?

upload_2016-11-16_13-29-23.png

Homework Equations

The Attempt at a Solution


a
J=Favg*t
200N/2*.01seconds=1kgm/s
J=Δp=0-.25kg*4m/s= -1 kgm/s
The impulse should be positive since its asking for the impulse on the wall and not the snow ball correct? I should have had
.25kg*4m/s-0= 1 kgm/s ?
b,
Since the graph is of isosceles triangles I can just divide the max F by 2 to get 200N/2=100N
Or use:
Favg=m*v/t
=(.250kg*4m/s)/.01s
=100 N
c.
should just be the maximum force divided by the time interval between the peak of two impacts?
200N/.05s
4000N/s?
 
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For c:
Favg=m*v/t?
=(.250kg*4m/s)/.05s
20N
 
Apart from the mass of a snowball, you did not state any input numbers. I deduce you were told the impact velocity, the impact duration, the impact separation, and, redundantly, the peak force. As far as I can tell, your working is all correct.
 
I should have looked at how the copy/paste had actually performed when posting the problem
 

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