In how many ways can a committee of 5 be selected from 35 members?

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SUMMARY

The discussion centers on the combinatorial problem of selecting a committee of 5 members from a total of 35 members. The correct approach to solve this problem involves using the combination formula, specifically C(35, 5), which calculates the number of ways to choose 5 members from 35 without regard to the order of selection. The calculation yields a total of 324632 ways to form the committee. The conversation highlights the importance of understanding mathematical concepts rather than seeking direct answers.

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In how many ways can a committee of 5 be selected from 35 members?
 
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This won't work, diceyfume.

You are obviously refusing to utilize your intellect, and are only interested in being spoonfed "answers".

I strongly advise you to quit maths, because your attitude makes you incompetent in it.
 

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