In the circular motion below, what will be the velocity?

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SUMMARY

The discussion centers on calculating the change in velocity in circular motion, specifically when both initial and final velocities are given as 2 m/s. The participants clarify that the change in velocity is calculated as Vf - Vi, resulting in -4i, while also addressing confusion regarding the distinction between change in velocity and acceleration. The correct acceleration is calculated as -0.8 m/s², but the participants emphasize that the question pertains to velocity change, not acceleration. The need for clearer diagrams and proper vector representation is also highlighted.

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HCverma
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Homework Statement


In circular motion what will be the change in velocity if initial velocity and final velocity is 2 m/s? From the left, in the 3rd diagram, if initial velocity and final velocity is 2 m/ s then what is the change in velocity? t = 5 s

Homework Equations

The Attempt at a Solution


the answer should be.
Acceleration = Vf - Vi / t = (-2i) - 2i / 5 = -4i / 5 = -0.8 m/s^2 but the answer is 0.8m/s^2.
 

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  • circular-motion-2-1024.jpg
    circular-motion-2-1024.jpg
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I see two illegible drawings (pure black) and something in the middle with some semi-legible chicken scratchings.
 
I think you should re-state the problem and provide readable drawing, it is not clear to me. Hint: velocity is a vector, giving value like "2 m/s" is not sufficient.
 
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HCverma said:

Homework Statement


In circular motion what will be the change in velocity if initial velocity and final velocity is 2 m/s? From the left, in the 3rd diagram, if initial velocity and final velocity is 2 m/ s then what is the change in velocity? t = 5 s

Homework Equations

The Attempt at a Solution


the answer should be.
Acceleration = Vf - Vi / t = (-2i) - 2i / 5 = -4i / 5 = -0.8 m/s^2 but the answer is 0.8m/s^2.
I have edited the image so that you can understand. Please see the image and let me know.
 

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  • circular-motion-2-1024.jpg
    circular-motion-2-1024.jpg
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HCverma said:
In circular motion what will be the change in velocity if initial velocity and final velocity is 2 m/s?
the answer should be.
Acceleration = Vf - Vi / t = (-2i) - 2i / 5 = -4i / 5 = -0.8 m/s^2 but the answer is 0.8m/s^2.
The question asks for a change in velocity but the answer is an acceleration? That's wrong.
 
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HCverma said:
(-2i) - 2i

How can both velocity vectors have same unit vector?

According to your drawing the first one, one is along j and another along i.

The pictures are still not clear. What are you using?
 
jbriggs444 said:
The question asks for a change in velocity but the answer is an acceleration? That's wrong.
Yes, my question is that in the picture change in velocity is 4 or -4, As I know the change in velocity is Vf -Vi = (-2i) - 2i = -4i. please see the picture.
 

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  • circular-motion-2-1024.jpg
    circular-motion-2-1024.jpg
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e-pie said:
How can both velocity vectors have same unit vector?

According to your drawing the first one, one is along j and another along i.

The pictures are still not clear. What are you using?
Could you suggest an online editor where I could sharpen my image as much clear as I can?
 
HCverma said:
Yes, my question is that in the picture change in velocity is 4 or -4, As I know the change in velocity is Vf -Vi = (-2i) - 2i = -4i. please see the picture.
I would say that the change in velocity is neither 4 nor -4. It is -4i.
 
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  • #10
jbriggs444 said:
I would say that the change in velocity is neither 4 nor -4. It is -4i.
would you please let me know whether you could understand my edited image I provided so that in future I would edit my images to that degree. Is it readable?
 

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  • circular-motion-2-1024.jpg
    circular-motion-2-1024.jpg
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  • #11
HCverma said:
would you please let me know whether you could understand my edited image I provided so that in future I would edit my images to that degree. Is it readable?
It is not pretty, but it is magnified enough that I can read it.
 
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  • #12
jbriggs444 said:
It is not pretty, but it is magnified enough that I can read it.
Ok, Thanks a lot for your kind reply.
 
  • #13
jbriggs444 said:
I would say that the change in velocity is neither 4 nor -4. It is -4i.
It is not clear to me whether the use of complex variables to represent the vectors comes from the original problem or has been introduced by the student.
@HCverma , please state the problem as given to you, word for word.
 
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  • #14
haruspex said:
It is not clear to me whether the use of complex variables to represent the vectors comes from the original problem or has been introduced by the student.
@HCverma , please state the problem as given to you, word for word.
Next time I will.
 
  • #15
HCverma said:
Next time I will.
Why not this time? As I understand it, you still lack an explanation for the book answer.
 
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