Increase RPM & Calculate Torque with Gearbox

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SUMMARY

To achieve a target output RPM of 1500 from an input RPM of 10, a speed-increasing gearbox with at least three stages is necessary to provide a 150x increase in RPM. Significant power losses must be considered, and the specific application will dictate the required torque at 1500 RPM. A potential solution involves using a large shaft hydraulic pump driving a small shaft hydraulic motor, where the pump has 150 times the displacement of the motor. Additionally, Föttinger clutches and torque converters, commonly used in automotive applications, may also be relevant but are not the primary focus of this discussion.

PREREQUISITES
  • Understanding of gearbox stages and their impact on RPM
  • Knowledge of hydraulic systems, specifically hydraulic pumps and motors
  • Familiarity with torque calculations using the formula: Power = Torque * RPM
  • Basic concepts of overdrive mechanisms in automotive applications
NEXT STEPS
  • Research the design and operation of multi-stage gearboxes
  • Explore the principles of hydraulic pump and motor displacement ratios
  • Learn about the applications and mechanics of Föttinger clutches
  • Investigate the role of torque converters in automotive engineering
USEFUL FOR

Engineers, mechanical designers, and automotive enthusiasts looking to understand gearbox design, hydraulic systems, and torque calculations for applications requiring significant RPM increases.

kotsios7
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Hi guys,
i would like to ask
how do i increase my rpm using a gearbox (2,3,4 stages i don't mind)
Input rpm 10 target output rpm 1500 and after that how can i calculate my torque?
 
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Welcome to the forum.

A speed increasing gearbox will probably need at least 3 stages to give a 150 x increase in RPM.
There will be significant losses. The practical solution will be dependent on how much power output you require.
What is the application? How much torque do you require at 1500 RPM?

Power = torque * RPM

There is possibly a single stage solution. A big shaft hydraulic pump driving a small shaft hydraulic motor where the pump has 150 times the displacement of the motor would achieve the required ratio.
 
Baluncore said:
There is possibly a single stage solution. A big shaft hydraulic pump driving a small shaft hydraulic motor where the pump has 150 times the displacement of the motor would achieve the required ratio.

Föttinger clutch and the Torque converter come to mind. Porsche uses them in their SUV. But,what the OP is talking about is the 5th gear i.e overdrive.
Baluncore:
How the 'Turbine'(the output side) is made to spin faster than the flywheel side(input side) just by pumping-in more oil has always been a mystery(to me). Could you please clear that up? I know the structure and working principle of the hydraulic coupling. But,its overdrive characteristics are always left to merky insider info. People say its the KERS unit that kicks-in as the overdrive but I'm not really sure...
 
kotsios7 is asking about a 10 RPM = 1 rev per 6 seconds. That is a very big windmill or a water wheel.
The 1500 RPM output speed is the same as an electric motor or generator.

I was suggesting positive displacement hydraulic components.

So, I don't think this thread is about a torque converter used in a vehicle.
Questions about torque converters would probably be better under engineering/mechanical/automotive.
http://en.wikipedia.org/wiki/Torque_converter
 

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