Given a convolution:(adsbygoogle = window.adsbygoogle || []).push({});

\begin{equation}

\begin{split}

g(x) * h(x) &\doteq \int_{-\infty}^{\infty} g(z) h(x-z) dz

\end{split}

\end{equation}

Do ##z## and ##x## have to be independent? For example, can one set ##x=z+y## such that:

\begin{equation}

\begin{split}

\int_{-\infty}^{\infty} g(z) h(x-z) dz&=\int_{-\infty}^{\infty} g(z) h(y) dz

\end{split}

\end{equation}

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# I Independence of variables in Convolution

Tags:

Have something to add?

Draft saved
Draft deleted

**Physics Forums | Science Articles, Homework Help, Discussion**