Inequalities With Parity-Specific Domains

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SUMMARY

The discussion centers on the challenge of combining two inequalities, X≥(2b-2)/(2a+1)-1 and Y≥(2b)/(2a+1)-2, while maintaining the conditions that X is an even integer and Y is an odd integer. The user seeks a more elegant formulation but is advised that any attempt to consolidate these inequalities may result in a loss of information. A suggested relationship is X>Y≥(2b)/(2a+1)-2>(2b-2)/(2a+1)-1, contingent on the values of a and b.

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Chelonian
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When I was working on a rather difficult real-life math problem, I nearly found the solution. What I came up with was two inequalities: ##X≥\frac{2b-2}{2a+1}-1## and ##Y≥\frac{2b}{2a+1}-2## and the fact that ##X>Y##. However, ##X## must be an even integer and ##Y## must be an odd integer. Is there any way of combining all of these statements into one nice, neat equation, or do I have to leave it in the unpleasant form in currently exhibits? I would truly hate to have all of the work I went through thus far on this problem end with such an ugly solution. I have struggled for about two or three hours, so any help you can give on this topic is greatly appreciated. Thank you for your time, and for any assistance you can provide.
P.S. Last time I posted a topic, it was recommended that I post my mathematical ability, so I am a mathematically advanced student in tenth grade.
 
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It's not quite clear what you want to achieve. The result looks fine to me and any combination into one inequality will lose information. Maybe one can relate the quotients to get an inequality ##X>Y\geq \frac{2b}{2a+1}-2 > \frac{2b-2}{2a+1}-1## but this depends on ##a## and ##b##.
 

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