Nontrivial Diophantine Solutions

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Discussion Overview

The discussion centers around the Diophantine equation 2x5 - y3 = 1, specifically exploring whether the only positive integer solution is x = 1 and y = 1. The scope includes mathematical reasoning and exploration of potential proofs.

Discussion Character

  • Exploratory, Mathematical reasoning

Main Points Raised

  • One participant inquires about proving that the only positive integer solution to the equation is x = 1 and y = 1.
  • Another participant suggests rewriting the equation as 2x5 = (y + 1)(y2 - y + 1) and notes that this implies 2 divides (y + 1) since (y2 - y + 1) is odd.
  • A third participant expresses confusion regarding the notation 2 | (y + 1).
  • A subsequent reply clarifies that the notation means '2 is a factor of (y + 1)'.

Areas of Agreement / Disagreement

The discussion includes some clarification of mathematical notation, but there is no consensus on the proof of the solution or the implications of the rewritten equation.

Contextual Notes

Participants have not yet provided a complete proof or addressed all assumptions related to the equation, leaving some steps unresolved.

e2m2a
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TL;DR
Existence of non-trivial positive integer solutions.
Given the diophantine equation: 2x^5 - y^3 = 1 Is there any way I can prove that the only positive integer solution for this equation is: x =1, y = 1?
 
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Why do you ask and what have you tried so far?

We could write ##2x^5=(y+1)(y^2-y+1)## and then we get ##2\,|\,(y+1)## because ##y^2-y+1## is odd.
 
Sorry, I don't know what you mean by the notation 2|(y+1)?
 
It means '2 is a factor of (y + 1)'. I'm not sure if @fresh42 meant to say anything more?
 

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