Inequality Solution [ , +Part solution included]

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Homework Help Overview

The discussion revolves around solving the inequality |3/(x-1) - 5| < 4, which involves absolute values and inequalities. Participants are exploring the implications of the inequality sign and the correct approach to isolate x.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the interpretation of the inequality and the steps taken to manipulate it. There is confusion regarding the correct range for x and whether the transformations applied are valid. Some suggest alternative methods to approach the problem.

Discussion Status

The discussion is ongoing, with participants providing insights and questioning the validity of certain steps. There is an acknowledgment of potential confusion in the methods being used, and some guidance has been offered regarding the conditions under which certain transformations hold true.

Contextual Notes

Participants are navigating the complexities of inequalities involving absolute values and are considering the implications of the signs in their manipulations. There is mention of previous discussions that may relate to this problem.

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Inequality Solution [URGENT, +Part solution included]

Homework Statement




l 3/(x-1) - 5 l < 4

Homework Equations





The Attempt at a Solution



so here's where I am abit confused. since the inequality sign is not > or >= but instead in this case it is <. Therefore, x has to be between two numbers.

But when i tried to solve l 3/(x-1) - 5 l < 4, it doesn't work out.
Heres my work:

-4 < 3/(x-1) - 5 < 4
1 < 3/(x-1) < 9
x-1 < 3 < 9x-9

you see.. this is nothing where its suppose to be.
i end up getting... bigger number < x < smaller number

am i going the wrong way? please help !
 
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Use the fact that if
[tex]a < \frac{1}{x} < b[/tex]

then

[tex]\frac{1}{a} > x > \frac{1}{b}[/tex] .
 


well here's a better question.

can i make the equation like this ?

1 < 3(x-1) < 9
x-1<3 or 3<9x-9
x < 4 or x > 4/3

Can this work too? 4/3 < x < 4
 


You can do that, but that method will be confusing if you ever work with inequalities that have unknowns instead of numbers.
 


Clarification:

[tex]a<\frac{1}{x}<b[/tex]
[tex]\implies\frac{1}{a}>x>\frac{1}{b}[/tex]

is only necessarily true if a and b are both negative or both positive. Sorry for the error.
 

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