Inertia, Gravitational Potential Energy

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Homework Help Overview

The problem involves a meter stick pivoted at one end, which is released from a horizontal position to swing downwards. The discussion focuses on concepts related to inertia and gravitational potential energy.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants express uncertainty about the initial conditions and how to approach the calculations. One participant suggests treating the meter stick as a point mass at its center of mass for potential energy calculations. Others clarify the setup of the problem, confirming the rotation about one end.

Discussion Status

The discussion is ongoing, with some participants providing hints and clarifications about the interpretation of the problem. There is no explicit consensus on the solution, but guidance has been offered regarding the approach to calculating gravitational potential energy.

Contextual Notes

Participants are grappling with the initial setup and the implications of the pivot point, as well as the assumptions involved in modeling the meter stick's motion.

jaredmt
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Homework Statement


A meter stick with a mass of .160kg is pivoted about one end so it can rotate without friction about a horizontal axis. The meter stick is held in a horizontal position and released. As it swings through the vertical, calculate (a) the change in gravitational potential energy that has occurred; (b) the angular speed of the stick; (c) the linear speed of the end of the stick opposite the axis. (d) Compare the answer in part (c) to the speed of a particle that has fallen 1.m, starting from rest.



The Attempt at a Solution



i have no idea, i can't even get the first part. i believe it is supposed to be something kind of like this sitting on a table:
445.jpg

and then they drop it while it is spinning?
idk i could use some help
 
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HINT: To calculate the the change in G.P.E you can treat the meter stick as a point particle of mass 0.16kg located at the centre of mass of the meter stick.
 
What I'm reading is if you held a meter stick in your hand parallel to the ground and then let it rotate down from the end you're holding so the opposite end falls while you still hold the end that was in your hand. That's rotating about one end of the meter stick.

Do correct me if I'm wrong.
 
@ above:
100 percent perfect interpretation.

@jaredmt:
The rod is in perfect rotation.
 

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