I think it helps to clarify first what we mean by inertial and gravitational mass.
Assume we have a way of measuring force, e.g. by spring compression. In a given gravitational field, we can thus find the weight of an object. Independently, we can find what acceleration is produced by subjecting the object to a known force, and define its inertial mass as F/a.
Thus we can find the weight (in a given field) and inertial mass of the same object.
Next, we observe that across different objects these are in a constant ratio, and we are therefore able to characterise the gravitational field strength as such-and-such an acceleration.
Having done that, we can define the gravitational mass as Fg/g; it follows that the two mass determinations are equivalent.
The observation that all bodies fall at the same acceleration starts, as we all know, with Galileo, but is also the cornerstone of General Relativity. Thus I would venture that the R proposition here is true, and that the correct answer to post #1 is (1).
Note that the given answer (2) to post #12 claims that this same R clause is true, thereby contradicting the book answer to the post #1 problem.
So what about R leading to A in post #12? First, what does it mean to say that the man experiences no gravity?
Each day we experience gravity by the fact that the ground has to exert a force upwards on us for us to stay in the 'same' place. The man's failure to experience gravity consists of his staying in the same place (within the cabin) yet feel no applied force. This happens because he and the cabin accelerate equally in the same gravitational field. It follows that this is equivalent to Galileo's observation.
As I showed above, that is considered explained by the equivalence principle. So, again, I would mark (1) as correct.