Inextensible cords passing over frictionless pulleys

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Homework Help Overview

The problem involves two blocks connected by inextensible cords over frictionless pulleys, with different coefficients of friction at two points. The objective is to compute the magnitude and direction of the friction forces acting on each block.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup and calculations involving angles and tensions for each block, referencing the sine law and the coefficient of friction. Some express uncertainty about the need for maximum friction calculations and the appropriate formulas to use.

Discussion Status

Some participants have provided insights into drawing Free Body Diagrams and considering the relationships between tensions and accelerations. There is an ongoing exploration of the necessary formulas and concepts, with no explicit consensus reached yet.

Contextual Notes

Participants note the requirement to find the tension in the cords and the importance of understanding the forces acting on the blocks, including friction. The discussion reflects a lack of clarity regarding the setup and the calculations involved.

apprentice213
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Homework Statement


the blocks shown in the figure are connected by flexible, inextensible cords passing over frictionless pulleys. at A, the coefficient fiction is 0.30 while at B, it is 0.40. compute the magnitude and direction of the friction forces and each block.
am i right ? x( please help .. want to learn
untitled.jpg


Homework Equations



for block A:
teta(A)=tan^-1(o.30)
teta(A)=16.70
N 53.13 W
sine law:
T/sine53.13=300/sin36.87
T=400lbs

for block B:
teta(B)=tan^-1(0.40)
teta(B)=21.80
N 36.87 E
sine law:
T/sin36.87=200/sin53.13
T=150lbs

The Attempt at a Solution

 
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apprentice213 said:

Homework Statement


the blocks shown in the figure are connected by flexible, inextensible cords passing over frictionless pulleys. at A, the coefficient fiction is 0.30 while at B, it is 0.40. compute the magnitude and direction of the friction forces and each block.
am i right ? x( please help .. want to learn
untitled.jpg


Homework Equations



for block A:
teta(A)=tan^-1(o.30)
teta(A)=16.70
N 53.13 W
sine law:
T/sine53.13=300/sin36.87
T=400lbs

for block B:
teta(B)=tan^-1(0.40)
teta(B)=21.80
N 36.87 E
sine law:
T/sin36.87=200/sin53.13
T=150lbs

The Attempt at a Solution


I can't really see the set-up but can only advise that the usual calculation Friction = uR calculates the maximum possible friction. Perhaps in this case you don't need, and thus won't generate the maximum friction?
 


2.jpg


sorry :) this is the figure . my instructor said we must find the tension(that red line) .. what should be the possible formula?
 


then this the 1st thing i do

3-1.jpg


could it be solve by this figure ?

then followed by law of sine
 
Last edited:


The force supporting each block in position comes in part by friction, and with a rope making up the difference. Friction may be acting up, or down, the slope, according to which way the block is tending to slide.
 
Last edited:


what would be the possible formula sir? because i can't really understand this topic although i tried my best to solve .. please help thnx
 


anyway this topic is related to Newtons law of motion
 


You should draw Free Body Diagrams for both blocks, showing the forces acting. Given the mass of a block and the expression for the net force you should be able to write an expression for the acceleration of each block. These expressions will contain the (as yet) unknown values of the tensions in the two ropes.

Next examine the original figure and determine the relationships between the two accelerations and the two tensions that will be enforced by the pulley setup. You should then have enough information to solve for the tensions.
 


thnx sir :)
 

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