Does the Limit of x^4 * 0.99^x as x Approaches Infinity Equal Zero?

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The limit of x^4 * 0.99^x as x approaches infinity is confirmed to equal zero. The discussion clarifies that while x^4 increases towards infinity, the term 0.99^x decreases to zero at a faster rate, leading to the overall limit being zero. There was some confusion regarding notation and terminology, particularly the use of "F" and "f" and the term "infinite indice." The participants emphasized that for any function of the form F(x) = a^x where 0 < a < 1, the limit approaches zero. Ultimately, the conclusion is that lim(+infinity) x^4 * 0.99^x = 0.
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hey

if let's say : F(x) = 0.5^x , 0 < 0.5 < 1

is lim(+infinte) f = 0 ?

.............

this is for one of my math questions :

lim (+infinite) x^4 * 0.99^x = ?
 
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Impossible to say, since you haven't said what f is, only F.

And yes, we DO know that 0.5 lies between 0 and 1.

What is meant by infinite indice is beyond me.
 
WE have the sequence 1/2, 1/4, 1/8...,obviously the nth term gets as close to zero as we like, and so 0 is the least upper bound and since it is never less than zero, the limit is 0.
 
ok then

lim (+infinite) x^4 * 0.99^x = 0

thanks
i just had a little dougthBTW : arildno ;
- for the F and f problem
> i just made a caps mistake
- for the 0 < 0.5 < 1
> it was because the F(x) = 0.5^x was an example for any function F(x)= a^x, where a is a real number that respects (0 < a < 1)
- for "infinite indice"
> it was just to make short
 
robert Ihnot said:
WE have the sequence 1/2, 1/4, 1/8...,obviously the nth term gets as close to zero as we like, and so 0 is the least upper bound and since it is never less than zero, the limit is 0.

No, 0 is the greatest lower bound. 1/2 is the least upper bound.
 
JPC said:
ok then

lim (+infinite) x^4 * 0.99^x = 0

thanks
i just had a little dougth


BTW : arildno ;
- for the F and f problem
> i just made a caps mistake
- for the 0 < 0.5 < 1
> it was because the F(x) = 0.5^x was an example for any function F(x)= a^x, where a is a real number that respects (0 < a < 1)
- for "infinite indice"
> it was just to make short

If you mean \lim_{x\right arrow +\infnty} x^4 * 0.99^x then it is true that 0.99x goes to 0 but it does NOT follow from that alone that the whole thing goes to 0 because x^4 goes to infinity.

It happens that the limit of x40.99x is 0 because 0.99x goes to 0 faster than x4 goes to infinity0- but that has to be shown.

If, as your use of "x" rather than "n" indicates, you intended this to be a continuous limit, then x is not an "index" at all. (There is no such word as "indice" in English. "Indices" is the plural of "index".
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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