Loren Booda Messages 3,115 Reaction score 4 Thread starter Sep 16, 2009 #1 [tex]?=\prod_{n=1}^\infty(n/(n+1))[/tex]
CRGreathouse Science Advisor Homework Helper Messages 2,832 Reaction score 0 Sep 16, 2009 #2 Let [tex]P(N)=\prod_{n=1}^N\frac{n}{n+1}.[/tex] Then you're looking for [itex]\lim_{n\to\infty}P(n).[/itex] P(1) = 1/2, P(2) = 1/2 * 2/3 = 1/3, P(3) = ... do you see what's going on here? What's the limit going to be?
Let [tex]P(N)=\prod_{n=1}^N\frac{n}{n+1}.[/tex] Then you're looking for [itex]\lim_{n\to\infty}P(n).[/itex] P(1) = 1/2, P(2) = 1/2 * 2/3 = 1/3, P(3) = ... do you see what's going on here? What's the limit going to be?
rrronny Messages 7 Reaction score 0 Sep 16, 2009 #3 [tex]\lim_{N \to \infty}P(N) = \lim_{N \to \infty} \frac{1}{N+1} = 0.[/tex]
Loren Booda Messages 3,115 Reaction score 4 Sep 16, 2009 #4 Thank you, CR. I just needed a little shaking up.