Infinity geometric series question

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Discussion Overview

The discussion revolves around solving a problem related to an infinite geometric series, specifically finding the common ratio \( r \) given the sum to infinity and the second term of the series. The scope includes mathematical reasoning and problem-solving techniques related to geometric series.

Discussion Character

  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents a problem involving the sum to infinity of a geometric series and seeks to find the common ratio \( r \) given specific values.
  • Another participant suggests that if the second term is \( r \) times the first term, then the first term can be expressed as the second term divided by \( r \).
  • A later reply confirms the relationship between the first term and the second term, stating that \( a = -2/r \) and provides a formula to solve for \( r \).

Areas of Agreement / Disagreement

Participants generally agree on the relationships between the terms of the geometric series, but the discussion remains unresolved regarding the specific value of \( r \) as they have not yet solved the equation.

Contextual Notes

There are limitations regarding the assumptions made about the values of \( a \) and \( r \), and the mathematical steps to solve for \( r \) have not been fully elaborated or resolved.

Emma O'shea
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Hi there everyone!
Have a quick question for you.
The question is:
The sum to infinity of a geometric series is 9/2
The second term of the series is -2
Find the value of r, the common ratio of the series.

I understand that we have to use the sum to infinity of a geometric series formula which is S(infinity) = a/1-r

where a is the first term in the series and r is the common ratio.
I also understand that s2 = s1*r.

We're given the second term...but how do we get a? our first term?
Any thoughts?
:cool:
 
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if you understand the second term is r times the first term, then you understand the first time is what times the second term?
 
The first term is the second term over r.
Well spotted!
I'll get the hang of this stuff yet!
:))
Thanks very much
 
So you now know that a= -2/r and that
[tex]\frac{a}{1-r}= \frac{-2}{r(1-r)}= 9/2[/tex]
Solve for r.
 
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