Values of x for which a geometric series converges

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SUMMARY

The discussion centers on determining the values of x for which the geometric series defined by the terms sin(x), sin(2x), and 4sin(x)cos²(x) converges. The common ratio identified is 2cos(x). For the series to converge, the absolute value of the common ratio must be less than one, leading to the condition |2cos(x)| < 1. This translates to the requirement that -1/2 < cos(x) < 1/2, which defines the specific intervals for x within the range -π/2 < x < π/2.

PREREQUISITES
  • Understanding of geometric series convergence criteria
  • Knowledge of trigonometric functions, specifically sine and cosine
  • Familiarity with the formula for the sum of an infinite geometric series, S∞ = u/(1-r)
  • Basic algebraic manipulation skills to solve inequalities
NEXT STEPS
  • Study the conditions for convergence of geometric series in detail
  • Learn how to derive and manipulate trigonometric inequalities
  • Explore the implications of the unit circle on trigonometric functions
  • Investigate the behavior of the cosine function within specified intervals
USEFUL FOR

Students preparing for exams in calculus or trigonometry, educators teaching geometric series, and anyone seeking to understand the convergence of trigonometric series.

ellaingeborg
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Need help with a homework question!
The question gives: The first three terms of a geometric sequence are sin(x), sin(2x) and 4sin(x)cos^2(x) for -π/2 < x < π/2.
First I had to find the common ratio which is 2cos(x)
Then the question asks to find the values of x for which the geometric series sinx + sin2x + ... converges.
I am not sure how to go about this question.
I tried using
S∞= u/(1-r) where r is the common ratio, u is the first term of the sequence and S∞ the sum of the series.
this sum would equal
sinx/(1-2cosx)

Please help! My finals are coming up and I need to know this thank you :)
 
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ellaingeborg said:
Need help with a homework question!
The question gives: The first three terms of a geometric sequence are sin(x), sin(2x) and 4sin(x)cos^2(x) for -π/2 < x < π/2.
First I had to find the common ratio which is 2cos(x)
Then the question asks to find the values of x for which the geometric series sinx + sin2x + ... converges.
I am not sure how to go about this question.
I tried using
S∞= u/(1-r) where r is the common ratio, u is the first term of the sequence and S∞ the sum of the series.
this sum would equal
sinx/(1-2cosx)

Please help! My finals are coming up and I need to know this thank you :)
A geometric series converges if |r| < 1. What does this mean in relation to your geometric series?

In the future, please do not delete the three parts of the homework template. It is required for homework questions.
 

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