Initial velocity and angle from position equations x(t) and y(t)

[borow039]

A ball is moving through the air as shown. Its horizontal position x and vertical position y can be described by two functions: x(t) = a + b*t and y(t) = c + d*t + e*t*t.
Here t represents time and

a= 84 cm, b=27 cm/s, c=88 cm, d=46 cm/s and e=-490 cm/s/s.

What is the magnitude of the initial velocity of the ball? and what is the angle between the initial velocity and the horizontal?

Could anyone provide a much needed hint to get going on this problem?

 

[rl.bhat]

Find dx/dt and dy/dt. That will give you vx and vy. Put t = 0 to get vo = sqrt(vx^2 + vy^2)

 

[borow039]

ok i got it thanks so much!