Undergrad Injectivity equivalent to having a left inverse

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SUMMARY

A function is injective if and only if it possesses a left inverse, which can be intuitively understood through the concept of function composition. Specifically, when applying a left inverse, denoted as ##f^{-1} \circ f(x)##, it effectively 'undoes' the function's action, ensuring that each output corresponds uniquely to an input. Conversely, a function has a right inverse if and only if it is surjective, as demonstrated by the composition ##f \circ f^{-1}(y)##, which is only defined for the range of the function. This relationship highlights the intrinsic connection between injectivity, surjectivity, and the existence of inverses.

PREREQUISITES
  • Understanding of function composition
  • Familiarity with the definitions of injective and surjective functions
  • Knowledge of left and right inverses in mathematics
  • Basic grasp of mathematical notation and terminology
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  • Study the properties of injective functions in detail
  • Explore the concept of surjective functions and their implications
  • Learn about the role of function inverses in algebra
  • Investigate the relationship between bijective functions and their inverses
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Mathematicians, educators, and students studying advanced algebra or functional analysis, particularly those interested in the properties of functions and their inverses.

Mr Davis 97
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I know that one can easily prove the result that a function is injective if and only if that function has a left inverse. But is there intuitive reason for this? Same goes for the fact that having a right inverse is equivalent to being surjective. Why are the properties of injectivity and sujectivity related to inverses?
 
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When a left inverse is applied to a function, as in ##f^{-1}\circ f(x)##, it 'undoes' the effect of the function because, under the right-to-left rule for function composition, ##f^{-1}## is applied after ##f##. If the function was not injective ##f^{-1}## could not map back to the original ##x## because there would be more than one possibility.

When a right inverse is applied, as in ##f\circ f^{-1}(y)##, the right inverse ##f^{-1}## will not be defined on all elements of its domain - which is the range of ##f## - if ##f## is surjective.
 
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