Instantaneous Speed Homework - Caltech: Mechanical Universe

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Homework Help Overview

The discussion revolves around the concept of instantaneous speed as presented in the Caltech series "The Mechanical Universe." Participants are exploring the relationship between different velocity formulas, specifically V(t) = 2ct and v = vi + gt, and their applications in various scenarios, such as free-falling objects and roller coasters.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to reconcile the formula V(t) = 2ct with the more commonly known formula v = vi + gt, questioning the contexts in which each applies. There is an exploration of the meaning of variables in these formulas and their implications for understanding instantaneous speed.

Discussion Status

Some participants are providing insights into the specific situations that each formula describes, such as the vertical speed of a freely falling object and the context of a roller coaster in free fall. There is an ongoing exploration of the correct interpretation and application of these formulas, with some expressing confusion about their relationships.

Contextual Notes

Participants note that the video provides specific values, such as the distance fallen in the first second, which adds complexity to their understanding of the formulas. There is an acknowledgment of the challenge in expressing these concepts mathematically while grasping the underlying physics.

AntonJD
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Homework Statement


I have just been watching Caltech: The Mechanical Universe and I'm a little bit puzzled by the instantaneous speed section, i understand the concept, if you try d/t you're deviding by zero at a fixed point so you can instead calculate ahead and reduce down to find the answer but the formula is what is puzzling me. The video shows V(t) = 2ct and elsewhere I'm being told it's v = vi + gt. Can someone shed some light on this or point me in the right direction.


Homework Equations


V(t) = 2ct
v = vi + gt


The Attempt at a Solution


N/A
 
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AntonJD said:
The video shows V(t) = 2ct
What situation is that formula meant to describe?
and elsewhere I'm being told it's v = vi + gt.
That formula describes the vertical speed of a freely falling object, such as a ball tossed into the air. vi is the initial velocity; g is the acceleration due to gravity.
 
The formula was used to describe a roller coaster in free fall from a stopped position, and the formula was described as V(t) being velocity as a function of time, C as the distance which a body falls in the first second (which was given as 16ft or 5M). I've gotten myself so confused over this now that I've been trying to figure it out for about 2 hours, the most frustrating part is that I'm sure i understand the concept of it, just making sure i have the correct formula and expressing it as a formula is proving difficult.
 
AntonJD said:
The formula was used to describe a roller coaster in free fall from a stopped position, and the formula was described as V(t) being velocity as a function of time, C as the distance which a body falls in the first second (which was given as 16ft or 5M). I've gotten myself so confused over this now that I've been trying to figure it out for about 2 hours, the most frustrating part is that I'm sure i understand the concept of it, just making sure i have the correct formula and expressing it as a formula is proving difficult.
Perhaps the formula was V(t) = 2(c/t). That makes sense. c/t, which is distance traveled over time, gives the average velocity during that time. But the instantaneous velocity at the end of that time interval is twice that. (Note that it starts from rest.)
 

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