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Integer solutions to ax^2 + bx - cy^2 - dy = 0

  1. May 17, 2015 #1
    1. The problem statement, all variables and given/known data
    I am a hobbyist looking for solutions to ax^2 + bx - cy^2 - dy = 0 where all variables are integers and are non-zero. Is there a method of doing this effectively?

    2. Relevant equations


    3. The attempt at a solution
    I can look at the numbers produced by ax^2 + bx vs cy^2 + dy and see that they have a relationship: what I mean is if I manually find a pair of close numbers, difference = d, I find the next set of values is d+2 apart, then d + 4 and so on. So it looks as though there should be a method in algebraic terms for doing this.
     
  2. jcsd
  3. May 17, 2015 #2

    Svein

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    Of course, the trivial solution is (0, 0). Otherwise, rewrite the equation as [itex] x(ax+b)-y(cy+d)=0[/itex].
     
  4. May 17, 2015 #3
    Sorry I know the variables a, b, c, and d but I don't know x, y. It looks as though I might be able to do something with modular arithmetic given that both x(ax+b) and y(cy+d) now seem to both be integer multiples in other words either x or ax+b must necessarily contain some factors in common with y and cy+d. Is there a good way to find x,y? Thanks!
     
  5. May 17, 2015 #4
    http://www4a.wolframalpha.com/Calculate/MSP/MSP100420ag0a9de184i4e300006aa5e486371cg88e?MSPStoreType=image/gif&s=23&w=258.&h=46. [Broken]
    You can find solutions of y in the same way. Its a bit silly though as it requires you to know all but x. You can see intuitively the set of solutions from the form Svein put it in
    x(ax+b)−y(cy+d)=0
    Yeah you could do what your saying and then write out the set of solutions
     
    Last edited by a moderator: May 7, 2017
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