timon00 Messages 5 Reaction score 0 Thread starter Dec 4, 2004 #1 can anyone help me ?? i can't seem to do it i don't know what to do i tried by parts and substitution
can anyone help me ?? i can't seem to do it i don't know what to do i tried by parts and substitution
Tide Science Advisor Homework Helper Messages 3,072 Reaction score 0 Dec 4, 2004 #2 HINT: [tex]\int (\ln x)^2 dx = \int \frac {dx}{dx} (\ln x)^2 dx[/tex]
timon00 Messages 5 Reaction score 0 Dec 4, 2004 #3 sorry to say but i don't get that hint , can u exlain more please thanks
shmoe Science Advisor Homework Helper Messages 1,971 Reaction score 2 Dec 4, 2004 #4 When you tried integration by parts, how did you break it up? Do you know how to find the simpler integral [itex]\int\ln(x)dx[/itex] by parts?
When you tried integration by parts, how did you break it up? Do you know how to find the simpler integral [itex]\int\ln(x)dx[/itex] by parts?
Tide Science Advisor Homework Helper Messages 3,072 Reaction score 0 Dec 4, 2004 #5 It's just integration by parts: [tex]\int (\ln x)^2 dx = \int \frac {dx}{dx} (\ln x)^2 dx = x (\ln x)^2 - \int x \frac {d (\ln x)^2}{dx} dx[/tex] You should be able to handle the rest.
It's just integration by parts: [tex]\int (\ln x)^2 dx = \int \frac {dx}{dx} (\ln x)^2 dx = x (\ln x)^2 - \int x \frac {d (\ln x)^2}{dx} dx[/tex] You should be able to handle the rest.