Integral of the square of the Dirac delta function

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Homework Statement



[tex]\int \delta(t)^{2}[/tex] dt from -infinity to +infinty

Homework Equations



[tex]\int^{\infty}_{-\infty}\delta(t)dt = 1[/tex]

[tex]\int uv dt = u\int v dt - \int u^{'}(t)\int v dt dt[/tex]

[tex]\int^{b}_{a} f(x) dx = F(b) - F(a)[/tex]

[tex]\delta(-\infty) = \delta(\infty) = 0[/tex]

The Attempt at a Solution



[tex]\int \delta(t) . \delta(t) dt = \delta(t)\int \delta(t) dt - \int \frac{d \delta(t)}{dt} . \int \delta(t) dt dt = \delta(t).1 - \int \frac{d \delta(t)}{dt}dt = \delta(t) - \delta(t) = 0[/tex]
 
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The integral of delta(x)^2 is not defined, it's infinite. Is that really the problem you were given?
 
Last edited:
Dick said:
The integral of delta(x)^2 is not defined, it's infinite. Is that really the problem you were given?

Thank you for replying.
[tex]\delta(t)[/tex] is an energy signal. I'm trying to find out the energy of the signal.
I wonder why the integral came out to be zero. I want some expert advice, whether I have done the integral correctly or not, or if there is some other explanations.
 
anybody please answer to my problem.
why the integral turns out to be zero.